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2 years ago

Please help. Will mark Brainliest to whoever gets it right! :)

Mathematics

2 answers:

levacccp [35]2 years ago

6 0

Answer:

A's average speed is 100. I did this same thing and passed my grade.

erma4kov [3.2K]2 years ago

6 0

Answer:

Step-by-step explanation:

To answer the question we must find the Time of B.

This should be easy considering the fact that we have are given the Distance and the Speed.

$\frac{D}{S}$ = T

$\frac{60}{40}$ = 1.5 hours or 1 hour and 30 minutes

Now, we know both routes that the same amount of time.

Now we know both routes take 1 hour and 30 minutes

Now we divide 90 by 1.5 to get our Speed for A

$\frac{90}{1.5}$ = 60km/hr

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3 years ago

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The expression 3 ( 1 . 5 )^ t models the number of bacteria in a culture as a function of the number of hours since the culture

Masteriza [31]

Answer:

Step-by-step explanation:

Given

3 $(1.5)^{t}$

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3 years ago

PLEASE HELP!!! WILL REWARD!!

BabaBlast [244]

X+y+z=t
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3 years ago

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Select ALL the correct answers.

Marina CMI [18]

Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

Median A = 1/2(11) = 5.5th term = (2+2)/2 = 2

Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

Median A = 2 ; median B = 2

IQR B = 2.5 ; IQR A = 1.5 ; IQR B > IQR A

7 0

2 years ago

GIVING BRAINLIEST!!!!!

Mashutka [201]

Answer:

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1 year ago

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