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3 years ago

Do the rational numbers form a finite set?

Mathematics

1 answer:

zysi [14]3 years ago

6 0

Yea because the rationl numbers are diffrent form as a finite set

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Use the substitution methods to solve the system of equations. Choose the correct ordered pair. y=7x+8 y=x+20

krek1111 [17]

Answer:

Step-by-step explanation:

Solution by substitution method

y=7x+8

∴y-7x=8

and y=x+20

∴y-x=20

Suppose,

-7x+y=8→(1)

and -x+y=20→(2)

Taking equation (1), we have

-7x+y=8

⇒y=7x+8→(3)

Putting y=7x+8 in equation (2), we get

-x + 7x + 8 = 20

6x = 20-8

6x = 12

x= 12 / 6

x = 2

substitute for x in equation (3)

y = 7(x) + 8

y = 7(2) + 8

y = 22

4 0

2 years ago

(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

$\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x$

$\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x$

Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

$\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x$

$\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x$

$\cot^2 x = \cot^2 x$

8 0

3 years ago

Mrs. Jones wants to cover half of her 5 x 7 rectangular bulletin board with two different colors (white and black) as show in th

Vladimir [108]

5x7=35
35/2= 17.5(whichever unit you’re using)

6 0

3 years ago

I need help with 1 and 3 please

schepotkina [342]

For #1
city A's mean would be 10.5, then you would divide it by the number of numbers there is which is 5,So 10.5/5 is 2.1

city B's mean would be 11.6 then you would divide it by the number of numbers there is which is 5, So 11.6/5 is 2.32.

thats all I have don't know how to do #3 sorry

4 0

3 years ago

What is 240 divided by 6 using a double number line?

VMariaS [17]

Answer:

Step-by-step explanation:

You have to divid 240 by 6

5 0

3 years ago