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anastassius [24]
3 years ago
13

A line / passes through the point (-2, 5) and intersects the axis of the y at the same point as the line y = 3x-4. What is the e

quation for the line?​
Mathematics
1 answer:
djyliett [7]3 years ago
7 0

Answer:

y= -10

Step-by-step explanation:

y=3x-4

y=3*(-2)-4

y= -6-4

y= -10

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The midpoint between -7 and 8 is 1/2 t or f
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Answer:

  True

Step-by-step explanation:

The midpoint is the average of the values:

  (-7 +8)/2 = 1/2

6 0
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In order for a class trip to be scheduled, at least 30 students must sign up. So far, 23 students have signed up. Write and solv
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3 0
3 years ago
Simplify 5(2) x 5(5)x5
anastassius [24]
First you would have to multiply everything by the parenthesis
5*2=10
5*5=25
So your equation should look like this
10*25*5
Then multiply from left to right
10*25=250
250*5=1250
So the simplified form of this is 1250

Hope this helps!
3 0
3 years ago
Read 2 more answers
Write in standard form 2+4i over 1+i
Levart [38]
So hmm a conjugate, is pretty much just, the same binomial, but with a different sign in the middle, so, a + b, has a conjugate of a - b
or -a + b, has a conjugate of - a  - b, or c - d, has a conjugate of c +d, and so on

anyway, the idea being, to "rationalize" the expression, namely, getting rid of the pesky radical in the denominator

so, we'll multiply the expression by 1, since anything times 1 is just itself

however, bear in mind, that 1, can be a/a, or b/b, or cheese/cheese, or anything/anything

so, we'll multiply the top and bottom of the fraction, by the conjugate of the denominator

anyhow, that said   \bf \cfrac{2+4i}{1+i}\cdot \cfrac{1-i}{1-i}\implies \cfrac{(2+4i)(1-i)}{(1+i)(1-i)}\implies \cfrac{2-2i+4i-4i^2}{1-i^2}\\\\
-----------------------------\\\\
\textit{recall that }i^2=-1\\\\
-----------------------------\\\\
 \cfrac{2-2i+4i-4(-1)}{1-(-1)}\implies \cfrac{2+2i+4}{2}\implies \cfrac{6+2i}{2}\implies \cfrac{6}{2}+\cfrac{2i}{2}
\\\\\\
\boxed{3+i}
7 0
3 years ago
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