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VladimirAG [237]
3 years ago
7

How do I find the first four terms of the sequence?

Mathematics
1 answer:
vivado [14]3 years ago
8 0

well your first term is obviously 5, then substitite n for 2, 3, and 4

a2 = a1+5 --> a2 = 12

a3 = a2 +5 --> a3 = 17

a4 = a3+ 5 --> a3 = 22

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Tju [1.3M]
16 3 x the took a quiz
3 0
2 years ago
Please I need answers Factorize x²-6x+9
miskamm [114]

Answer:

The factors of the given equation are:

x^2-6x+9=(x-3)(x-3)=(x-3)^2

Step-by-step explanation:

We have :

x^2-6x+9

Using middle term splitting theorem to factorize the expression :

x^2-3x-3x+9

x(x-3)+(-3)(x-3)

(x-3)(x-3)

x^2-6x+9=(x-3)(x-3)=(x-3)^2

The factors of the given equation are:

x^2-6x+9=(x-3)(x-3)=(x-3)^2

4 0
3 years ago
Topic/what am learning:
zloy xaker [14]
4 7/8 + 11 1/2 = 16 3/8
4 + 7/8 + 11 + 1/2
4 + 11 = 15
7/8 + 1/2 = 7/8 + 4/8 = 11/8
11/8 = 1 3/8
15 + 1 + 3/8 = 16 3/8
3 0
2 years ago
2:1 next 3 equivalent ratios are
insens350 [35]

The next 3 equivalent ratios are

4:2

6:3

8:4

10:5


Hope this helps!


4 0
3 years ago
Read 2 more answers
Which step could be used to help isolate the variable in the following equation? 5.6j – 0.12 = 4 + 1.1j Subtract 0.12 from both
mylen [45]

Answer:

would be D.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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