Question

What would be the answer

Answer 1

Answer:

Third option

Step-by-step explanation:

Congruency by the AAS postulate

If 2 angles and a non- included side of one triangle are congruent to 2 angles and a non- included side of another triangle then the triangles are congruent.

Here ∠ABC ≅ ∠DEF and ∠ACB ≅ ∠DFE

The non- included side is AB ≅ DE

Answer 2

Answer:

$\overline{AB} \cong \overline{DE}$

Step-by-step explanation:

Under the AAS postulate, two triangles are congruent if any two angles and a non-included side are congruent in both. Therefore, if $\angle{B} \cong \angle{E}$ and $\angle{C} \cong \angle{F}$, then $\overline{AB}$ would need to be congruent to $\overline{DE}$ to prove that the two triangles are congruent. The other solution would be $\overline{AC} \cong \overline{DF}$, but that is not an answer choice.