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k0ka [10]
3 years ago
13

Please help (screenshot included)

Mathematics
2 answers:
Galina-37 [17]3 years ago
8 0
I Think it’s 26 hours! Hope it helps u!
umka2103 [35]3 years ago
4 0

Answer:

16 hours

Step-by-step explanation:

company A $800 plus $16 per hour

company B $720 plus $21 per hour

im going to start with 10 and go from there

company A

16 x 10 = 160

800 + 160 = 960

company B

21 x 10 = 210

720 + 210 = 930

it needs to go up so lets try 15

company A

16 x 15 = 240

800 + 240 = 1040

company B

21 x 15 = 315

720 + 315 = 1035

one more maybe 16

company A

16 x 16 = 256

800 + 256 = 1056

company B

21 x 16 = 336

720 + 336 = 10 56

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SHAYNA FREEL PLANS TO BUY $17.45 WORTH OF STATIONERY SUPPLIES. IF THE SALES TAX IS 13%, HOW MUCH WILL SHAYNA PAY?
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Answer:

  $19.72

Step-by-step explanation:

The sales tax is 13% of $17.45:

  0.13 × $17.45 = $2.27 . . . . . . rounded (up) to the nearest cent

Then the total Shayna will pay is ...

  $17.45 +2.27 = $19.72

7 0
3 years ago
Suppose you have 20 coins that total $4.00. Some coins are nickels and some are quarters. Which of the following pairs of equati
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A. n+q=45n+25q=20. That should be the correct answer
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Anna completed 40% of her homework . Her homework has 30 question how many problems does she still need to complete
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She still has to complete 18 problems!
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2 years ago
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A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.
noname [10]

Answer:

Width = 4ft

Height = 4ft

Length = 8ft

Step-by-step explanation:

Given

Volume = 128ft^3

L = 2W

Base\ Cost = \$9/ft^2

Sides\ Cost = \$6/ft^2

Required

The dimension that minimizes the cost

The volume is:

Volume = LWH

This gives:

128 = LWH

Substitute L = 2W

128 = 2W * WH

128 = 2W^2H

Make H the subject

H = \frac{128}{2W^2}

H = \frac{64}{W^2}

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

A = LW + 2(WH + LH)

The cost is:

Cost = 9 * LW + 6 * 2(WH + LH)

Cost = 9 * LW + 12(WH + LH)

Cost = 9 * LW + 12H(W + L)

Substitute: H = \frac{64}{W^2} and L = 2W

Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)

Cost =18W^2 +  \frac{768}{W^2}*3W

Cost =18W^2 +  \frac{2304}{W}

To minimize the cost, we differentiate

C' =2*18W +  -1 * 2304W^{-2}

Then set to 0

2*18W +  -1 * 2304W^{-2} =0

36W - 2304W^{-2} =0

Rewrite as:

36W = 2304W^{-2}

Divide both sides by W

36 = 2304W^{-3}

Rewrite as:

36 = \frac{2304}{W^3}

Solve for W^3

W^3 = \frac{2304}{36}

W^3 = 64

Take cube roots

W = 4

Recall that:

L = 2W

L = 2 * 4

L = 8

H = \frac{64}{W^2}

H = \frac{64}{4^2}

H = \frac{64}{16}

H = 4

Hence, the dimension that minimizes the cost is:

Width = 4ft

Height = 4ft

Length = 8ft

8 0
2 years ago
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