Using the binomial distribution, it is found that there is a 0% probability that fewer that 5 in a sample of 20 pills will be acceptable.
For each pill, there are only two possible outcomes, either it is acceptable, or it is not. The probability of a pill being acceptable is independent of any other pill, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- The sample has 20 pills, hence
.
- 100 - 4 = 96% are acceptable, hence

The probability that <u>fewer that 5 in a sample of 20 pills</u> will be acceptable is:

In which






0% probability that fewer that 5 in a sample of 20 pills will be acceptable.
A similar problem is given at brainly.com/question/24863377
Answer:
68
Step-by-step explanation:
Answer:
$9.35
Step-by-step explanation:
Tilapia: 1.5 * $3.88 = $5.82
Cod: 1 * 3.53 = $3.53
$3.53 + $5.82 = $9.35
Answer:
Step-by-step explanation:
Given that :
Number of teams = 14
Each team plays every other team twice ;
Using the combination formula :
nCr = n! ÷ (n-r)! r!
14C2 = 14! ÷ (14 - 2)! 2!
14C2 = 14! ÷ (12)! 2!
14C2 = (14 * 13) ÷ 2 * 1
14C2 = 182 / 2
14C2 = 91
Hence, since they are going to be playing each other twice :
2(14C2)
2 * 91 = 182games