Question

Drag values to complete each equation.

Answer 1

Answer:

1 and $8^{-1}$

Step-by-step explanation:

using the rules of exponents

• $(a^m)^{n}$ = $a^{mn}$

• $a^{m}$ × $a^{n}$ = $a^{(m+n)}$

•  $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$

given $(8^3)^{4}$ × $8^{-9}$ / $8^{3}$

= ($8^{12}$ × $8^{-9}$ ) / $8^{3}$

= $\frac{8^{12+(-9)} }{8^{3} }$ = $\frac{8^{3} }{8^{3} }$ = 1

given ($8^{3}$ × $8^{4}$) / $(8^2)^{4}$

= $\frac{8^{(3+4)} }{8^{8} }$

= $\frac{8^{7} }{8^{8} }$

= $8^{(7-8)}$ = $8^{-1}$