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Elena-2011 [213]
3 years ago
11

Factor 1.21a^6+22a^3+100

Mathematics
1 answer:
Monica [59]3 years ago
4 0

Answer:

\frac{1}{100} (11 {a}^{3} + 100)(11 {a}^{3} + 100)

Step-by-step explanation:

1.21 {a}^{6}  +  22 {a}^{3}  + 100 \\  = 1.21 {a}^{6}  +  11 {a}^{3}  +  11 {a}^{3}+ 100 \\  = 11 {a}^{3} (0.11 {a}^{3}  + 1) + 100(0.11 {a}^{3}  + 1) \\  = (0.11 {a}^{3}  + 1) (11 {a}^{3} + 100) \\  = ( \frac{11}{100}  {a}^{3}  + 1) (11 {a}^{3} + 100) \\ =   ( \frac{11{a}^{3}  + 100}{100}  ) (11 {a}^{3} + 100) \\  =  \frac{1}{100} (11 {a}^{3} + 100)(11 {a}^{3} + 100) \\ are \: the \: required \: factors.

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