Answer:
The number of teachers who teach physics n(P) = 12
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given that the number of teachers who teach mathematics or physics
n(MUP) = 20
Given that the number of teachers who teach mathematics
n(M) = 12
Given that the number of teachers who teach both mathematics and physics
n(M∩P) = 4
<u><em>Step(ii):-</em></u>
By using n(A∪B) = n(A) + n(B) - n(A∩B)
n(M∪P) = n(M) +n(P) - n(M∩P)
20 = 12 + n(P) - 4
20 -12 +4 = n(P)
n(P) = 12
<u><em>Final answer:-</em></u>
The number of teachers who teach physics n(P) = 12
<span>X+(X+1)=31
</span>x is the first number and the second number should be x+1, since they are consecutive
Answer:
x =10
Step-by-step explanation:
Using the pythagoras theorem om one of the right triangle;
(√74)² = (x/2)²+7²
74 = (x/2)²+49
(x/2)² = 74 - 49
(x/2)² = 25
Square root both sides
√ (x/2)² = ±√25
x/2 = ±5
x = 2 * ±5
x = ±10
Hence the value of x is 10
0.097- or it could be 0.10 if you round it
The difference between the 6th term and the 9th term of the sequence is 135
<h3>How to determine the difference</h3>
Given that the nth term is;
3n² + 11
For the 6th term, the value of n is 6
Let's solve for the 6th term
= 3( 6)^2 + 11
= 3 × 36 + 11
= 108 + 11
= 119
For the 9th term, n = 9
= 3 (9)^2 + 11
= 3( 81) + 11
= 243 + 11
= 254
The difference between the 6th and 9th term
= 254 - 119
= 135
Thus, the difference between the 6th term and the 9th term of the sequence is 135
Learn more about algebraic expressions here:
brainly.com/question/4344214
#SPJ1