If g(t) = 4 - 3t, then g(-2)=
1 answer:
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Answer:
21.38 minutes
Step-by-step explanation:
the total number served = 101
teh number of hours that is spent in serving from 11.30 to 1.30 = 2 hours
Lq = average number of those that are in line = 18 customers
from here we are to find the flow rate
=
= 101/2 = 50.5
the average time in waiting =
Lq/flow rate
= 18/50.5
= 0.3564 hours
convert to minutes = 0.3564 * 60 minutes
= 21.38 minutes
Answer:
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of . So we have T = 3.25
The margin of error is:
M = T*s = 3.25*25 = 81
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds
The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
There's nothing preventing us from computing one integral at a time:
Expand the integrand completely:
Then