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3 years ago

If g(t) = 4 - 3t, then g(-2)=

Mathematics

1 answer:

andrew11 [14]3 years ago

7 0

Plug -2 into the equation where t is, so 4 - 3( - 2 ). Multiply 3 and -2 first which is -6. 4 - (-6) is 4+6=10

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Rove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero.

liubo4ka [24]

Answer:

$\frac{ad+bc}{bd}$

Step-by-step explanation:

$Greetings!$

$I'm~Isabelle~Williams~and~I~will~be~answering~your~question!$

$Let,\frac{a}{b} ~and ~\frac{c}{d}~be~two~rational~numbers, ~where~ b ~and~ d ~are~ not~ zero ~and~ a, ~b, ~c ~and \\~d ~are~ integers.$

$1.~Given:$

$\frac{a}{b} +\frac{c}{d}$

$2.~Now,~we~multiply~to~get~a~common~denominator:$

$\frac{a}{b}+\frac{c}{d}=\frac{ad}{bd}+\frac{cb}{db}$

$3.~Then~simplify:$

$\frac{a}{b}+\frac{c}{d}=\frac{ad}{bd}+\frac{cb}{db}=\frac{ad+bc}{bd}$

$4.~Since,b\neq 0,~d\neq 0,~then,~bd,~ad,~bc~and~ad+bc~are~integers~too.~So~the\\ fraction~will~be:$

$\frac{ad+bc}{bd}$

$Thus,~making~it~a~rational~number!$

$Hope~this~answer~helps!~and~have~an~amazing~day~ahead!$

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anyanavicka [17]

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Then the partial fraction decomposition would take the form

$\dfrac{x^4}{(x^3+x)(x^2-x+7)} = \dfrac{a_0x + b_0}{x^2+1} + \dfrac{a_1x + b_1}{x^2-x+7}$

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2 years ago

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8090 [49]

$12a^2b^6=(2a)(6ab^6)\\\\28a^4=(2a)(14a^3)\\\\42ab^3=(2a)(21b^3)\\\\GCF(12a^2b^6,\ 28a^4,\ 42ab^3)=2a$

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3 years ago

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madreJ [45]

Answer:

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Step-by-step explanation:

hoped I helped:)

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