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algol13
3 years ago
7

Which products result in a difference of squares or a perfect square trinomial? Check all that apply.

Mathematics
2 answers:
tiny-mole [99]3 years ago
6 0

Answer:

Option B) (7x+4)(7x+4) is correct

The product result in a perfect square trinomial is

(7x+4)(7x+4)=49x^2+56x+14

Step-by-step explanation:

(7x+4)(7x+4)=(7x+4)^2 ( using (a+b)(a+b)=(a+b)^2 )

=(7x)^2+2(7x)(4)+4^2 ( using (a+b)^2=a^2+2ab+b^2 )

=7^2x^2+56x+16

=49x^2+56x+14

Therefore (7x+4)(7x+4)=49x^2+56x+14

which is a perfect square trinomial

A trinomial is a perfect square trinomial if it can be factored into a binomial multiplied to itself. In a perfect square trinomial, two terms will be perfect squares.

Option B) (7x+4)(7x+4) is correct

The product result in a perfect square trinomial is

(7x+4)(7x+4)=49x^2+56x+14

Basile [38]3 years ago
6 0

Answer:

A, (5x + 3)(5x – 3)

B, (7x + 4)(7x + 4)

E, (x – 9)(x – 9)

F, (–3x – 6)(–3x + 6)

Step-by-step explanation:

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Which rule deacribes the
Marysya12 [62]

Answer:

A. {T_{-6,-2}}\circ {r_{x-axis}}(x,y)

Step-by-step explanation:

We have that, ΔABC is transformed to get ΔA''B''C''.

We see that the following transformations are applied:

1. Reflection across x-axis i.e. flipped across x-axis.

Now, ΔABC is reflected across x-axis along the line AC to get ΔA'B'C'.

2. Translated 2 units down i.e. shifted 2 units down and and then translated 6 units to the left i.e. shifted 6 units to the left.

So, ΔA'B'C' is translated 2 units downwards and 6 units to the left to get ΔA''B''C''.

Hence, the sequence of transformations is Reflection across x-axis and then Translation of 2 units down and 6 units left.

6 0
3 years ago
Somebody pls help I’m doin a exam!!!!
ra1l [238]

Answer:

Step-by-step explanation:

12x+2y=36

2y=36-12x

5x+36-12x=22

7x=14

x=2

2y=36-12(2)

2y=12

y=6

btw,next time, please do not include words like(failing ,exam,test,etc) in your question,otherwise, the question might be deleted.

5 0
2 years ago
1/2x + 6= 3x - 4<br> Solve the system of equations
shepuryov [24]
1.Combine multiplied terms into a single fraction

2. Multiply by 1

3. Subtract 6 from both sides of the equation

4.Simplify

5.Subtract 3x from both sides of the equation

6.Simplify

7.Multiply all terms by the same value to eliminate fraction denominators

8.Simplify

9.Divide both sides of the equation by the same term

10.Simplify

Solution:x=4
5 0
2 years ago
given the midpoint of segment KL is M (1, -1) and L (8 ,-7) what are the coordinates of the other endpoint K
andrey2020 [161]

The answer is (-6, 5) for K.

In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Kx + Lx)/2 = Mx

(Kx + 8)/2 = 1

Kx + 8 = 2

Kx = -6

And now we do the same thing for y values

(Ky + Ly)/2 = My

(Ky + -7)/2 = -1

Ky + -7 = -2

Ky = 5

This gives us the final point of (-6, 5)

7 0
2 years ago
Read 2 more answers
Factor 4x^4yz-16y^3z
Iteru [2.4K]

Answer:

<h2>4x⁴yz - 16y³z = 4yz(x² - 2y)(x² + 2y)</h2>

Step-by-step explanation:

4x^4yz-16y^3z\\\\4x^4yz=4yz\cdot x^4\\\\16y^3z=4yz\cdot4y^2\\\\4x^4yz-16y^3z=4yz\cdot x^4-4yz\cdot4y^2=4yz(x^4-4y^2)\\\\x^4-4y^2=x^{2\cdot2}-2^2y^2=(x^2)^2-(2y)^2=(x^2-2y)(x^2+2y)\\\\Used:\\\\(a^n)^m=a^{nm}\\\\(ab)^n=a^nb^n\\\\a^2-b^2=(a-b)(a+b)\\\\4x^4yz-16y^3z=4yz(x^2-2y)(x^2+2y)


6 0
3 years ago
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