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The answer is A
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Answer:
A. ΔDGH ≅ ΔFEH
Step-by-step explanation:
We are given the proof of GH ≅ EH and DH ≅ FH.
Now, previous to step 7, we have obtained,
Step 5: ∠HGD ≅ ∠HEF and ∠HDG ≅ ∠HFE
Step 6: DG ≅ EF as opposite sides of a parallelogram are congruent.
Since, we have that two angles of the triangles are congruent and their including sides are also congruent.
Thus, by Step 7 i.e. ASA criterion for congruence, we get that the corresponding triangles are also congruent.
Hence, we get, ΔDGH ≅ ΔFEH.
Step-by-step explanation:
