Answer:
Volume = 8 * 3.5 * 14.5 =
406 cubic feet
.65 pounds / cubic foot * 406 =
263.9 pounds
Step-by-step explanation:
Answer:
s=7
Step-by-step explanation:
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
Answer:
$275
Step-by-step explanation:
So she put $60 into savings....
X is the amount of her paycheck...
after buying the clothes she had X-75
She spend (2/5)(x-75) on books
The amount deposited into saving and spent on groceries totals 120.
So
X = 75 + (2/5)(x-75) + 120
X = (2/5)(X-75) + 195
X = (2/5)X - 30 + 195
X = (2/5)X + 165
(3/5)X = 165
X = 165*5/3 = 5*55 = 275
Starts with 275
spent 75 on clothes, which makes it 200.
2/5 of 200 is 80, which makes it 120.
60 deposited into savings and 60 on groceries
Her paycheck was 275
Answer:
3x - 6
Step-by-step explanation:
Segment YB = x + 3
Segment BW = 2x - 9
Add the two segments.
x + 3 + 2x - 9
3x - 6
The diagonal YW is 3x - 6 units long.
