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AlexFokin [52]
3 years ago
5

Why is the letter i the square root of negative one (

"\sqrt{-1}" alt="\sqrt{-1}" align="absmiddle" class="latex-formula"> )?
Mathematics
1 answer:
Alja [10]3 years ago
3 0

Answer:

It is an imaginary number.

Step-by-step explanation:

The square root of negative one is "i," the imaginary number. This concept is immensely useful in mathematics, as it allows for there to be square roots of negative numbers, which is otherwise not possible using only real numbers.

Any number that includes a negative square root is called an imaginary number. For example, the square root of -9 equals 3i, an imaginary number. When an imaginary number and a real number are combined, for example 2 + 3i, this is called a complex number. Complex numbers have many real world applications, including manipulating sound waves and calculating electrical currents.

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a film canister in the shape of a cylinder has a height of 8 centimeters and a volume of the film canister. write an equation fo
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Answer:

Part a) The equation for the volume of the film canister is

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Part b) The radius of the film canister is 2\ cm

Step-by-step explanation:

<u><em>The complete question is</em></u>

A film canister in the shape of a cylinder has a height of  8 centimeters and a volume of 32π cubic centimeters.

a. Write an equation for the volume of the film canister.

b. What is the radius of the film canister?

Part a) Write an equation for the volume of the film canister

we know that

The volume of a cylinder is equal to

V=\pi r^{2} h

where

r is the radius of the circular base

h is the height of the cylinder

we have

V=32\pi\ cm^3

h=8\ cm

substitute

32\pi=\pi r^{2}(8) ----> equation for the volume of the film canister

Part b) What is the radius of the film canister?

we have

32\pi=\pi r^{2}(8)

32\pi=8\pi r^{2}

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