Answer:
Area segment = 3/2 π - (9/4)√3 units²
Step-by-step explanation:
∵ The hexagon is regular, then it is formed by 6 equilateral Δ
∵ Area segment = area sector - area Δ
∵ Area sector = (Ф/360) × πr²
∵ Ф = 60° ⇒ central angle of the sector
∵ r = 3
∴ Area sector = (60/360) × (3)² × π = 3/2 π
∵ Area equilateral Δ = 1/4 s²√3
∵ The length of the side of the Δ = 3
∴ Area Δ = 1/4 × (3)² √3 = (9/4)√3
∴ Area segment = 3/2 π - (9/4)√3 units²
