A is the answer. Since they will both be divided by 4 due to the same amount of points, because Globrite has a greater range, it will have a greater mean. Glo brite also ranges bigger than Luminate
Answer: 1/25
Step-by-step explanation:
So a times 10^n where 1≤|a|<10 and n is an integer is what i learned
so
a.
234=
2.34 times 100=
2.34 times 10²
b.
0.000052=
5.2 times 1/100000=
5.2 times 10⁻⁵
c.
-220000=
-2.2 times 100000=
-2.2 times 10⁵
d. ok, so just count the spaces moved to the left
-18.2 times 10⁻¹⁵
The right answer is A as the angle would be X to the power of 2 indicating A
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
