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Anvisha [2.4K]
3 years ago
11

Consider the tables that represent ordered pairs corresponding to a function and its inverse. When comparing the functions using

the values in the table, which conclusion can be made? According to the tables, f(x) does not have a y-intercept. According to the tables, f–1(x) does not have an x-intercept. The domain of f(x) is restricted such that x ≥ 0, so the domain of f–1(x) is restricted such that y ≥ 0. The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.

Mathematics
2 answers:
lara31 [8.8K]3 years ago
5 0

Answer:

D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.

Step-by-step explanation:

The missing tables are:

First table  

x:    0  1    2

f(x): 1   10  100

Second table

x:         1000   100   10

f^-1(x):  3          2       1  

Option A is not correct because f(x) has a y-intercept at (0, 1)

If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct

Option C is not correct because the domain of f^-1(x) is associated with x values.

Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa

Tasya [4]3 years ago
3 0

Answer: D

The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.

Step-by-step explanation:

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One line passes through the points (-7,5)
Studentka2010 [4]

Answer:

1. (-7, 5 ) and (-1, 3)

(3-5)/(-1+7)= -2/6 = -1/3

y - 5 = (-1/3)(x + 7)

y - 5 = (-1/3)x - 7/3

y - 15/3= (-1/3)x - 7/3

y = (-1/3)x + 8/3

2. (-1-3)/(3-0)= -4/3

y + 3 = (-4/3)(x + 1)

y + 3 = (-4/3)x - 4/3

y + 9/3 = (-4/3)x - 4/3

y = (-4/3)x + 5/3

the answer is neither

7 0
3 years ago
I need help asap!!!!!!!!!!!!
eimsori [14]

Answer:

121 books

Step-by-step explanation:

bc that equals 11 so there are 11 squares plus the two missing ones from before so u do 11x11 which would be 121

hope this helps :>

5 0
3 years ago
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
Frank stands 450 feet from the base of the Statue of Liberty. If the Statue of Liberty is 306 feet tall, what is the angle of de
Lelu [443]
<span>For the answer to the question above, We have a right angled triangle with an opposite of 300.5 ft. (306 - 5.5) and an adjacent of 400 ft. Recalling SOH CAH TOA, tanθ = O/A.
tan(θ) = 300.5/400.
θ = tan^-1(300.5/400).
So the answer is
θ = 36.9°.
I hope my answer helped you.</span>
6 0
3 years ago
Its like a word question?
Sloan [31]

Answer:

-3+x=x+4

Step-by-step explanation:

Pls Mark Brainliest

5 0
3 years ago
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