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Anvisha [2.4K]
4 years ago
11

Consider the tables that represent ordered pairs corresponding to a function and its inverse. When comparing the functions using

the values in the table, which conclusion can be made? According to the tables, f(x) does not have a y-intercept. According to the tables, f–1(x) does not have an x-intercept. The domain of f(x) is restricted such that x ≥ 0, so the domain of f–1(x) is restricted such that y ≥ 0. The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.

Mathematics
2 answers:
lara31 [8.8K]4 years ago
5 0

Answer:

D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.

Step-by-step explanation:

The missing tables are:

First table  

x:    0  1    2

f(x): 1   10  100

Second table

x:         1000   100   10

f^-1(x):  3          2       1  

Option A is not correct because f(x) has a y-intercept at (0, 1)

If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct

Option C is not correct because the domain of f^-1(x) is associated with x values.

Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa

Tasya [4]4 years ago
3 0

Answer: D

The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.

Step-by-step explanation:

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If 3x + 2y = 1 and<br> 2x + 7y = 3<br><br> How do you find x and y step by step?
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Step-by-step explanation:

there are 2 main approaches (in their core they are the same, of course, but they look different) :

1. use one equation to express one variable by the second, and then use this in the second equation to solve for the remaining variable. with that you go back into the first equation and solve for the first variable.

2. multiply both equations by certain factors as needed, then add both results, so that there is one summary equation with only one variable, and then solve for it. then use that in one of the original equations and solve for the second variable.

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