A population of mice has black or brown hair. The gene for black hair color (B) is dominant over brown (b). If 16% of the mice a
re homozygous black and 24% are heterozygous black, what would be the frequency of each allele?
1 answer:
B = 0.4
b = 0.6
Explanation:
From the question we derive that;
BB = 16%
Bb = 24%
The gene frequency for BB = 16/100 = 0.16
To find allelic frequency of B;
B = √0.16 = 0.4
Remember Hardy Weinberg rule that all allelic frequencies of a gene must sum up to 1;
p + q = 1
If p = 0.4
q = 1 – 0.4 = 0.6
b = 0.6
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For more on allelic /genetic frequencies check out;
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