Answer:
weird
Step-by-step explanation:
Y = (3/2)x-1 tp find m count from one point the units up and to the right till you meet the second point. Y int. is there
4n² - 15n + 14<span> is always the product of two numbers, for it to be prime number, one of these factors must be either 1 or -1.
Case n - 2 = 1
That would be n = 3
Then </span>4n² - 15n + 14<span> = 5 , which is prime.
Case n - 2 = -1
That would be n = 1
Then </span>4n<span>² - 15n + 14 = 3, which is also prime.
Case 4n - 7 = 1
That would be n = 2 and that makes other factor (n-2) zero so it's not prime
Case 4n-7 = -1
That would be n = 3/2 which is not integer, so </span>4n<span>² - 15n + 14 will not be interger.
For any other n values, </span>4n<span>² - 15n + 14 will be composite number since it is product of two factors.
Therefore we are left with n = 1 and n = 3; only two values of n.</span>
-3x + 4y = 12
x - y = 1....x = y + 1
-3(y + 1) + 4y = 12
-3y - 3 + 4y = 12
-3y + 4y = 12 + 3
y = 15
x - y = 1
x - 15 = 1
x = 1 + 15
x = 16
one solution (16,15)
(2,7) is going to be the answer for that
