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musickatia [10]
3 years ago
8

The population of a town is 13,000. It decreases at a rate of 5% per year. In about how many years will the population be less t

han 12,000?
Mathematics
1 answer:
just olya [345]3 years ago
3 0

This is an exponential decay problem.

Using the equation Y = a *(1-rate)^time

where Y is the future value given as 12,000 and a is the starting value given as 13,000.

The rate is also given as 5%.

The equation becomes:

12,000 = 13,000(1-0.05)^x

12,000 = 13,000(0.95)^x

Divide each side by 13000:

12000/13000 = 0.95^x/13000

12/13 = 0.95^x

Use the natural log function:

x = ln(12/13) / ln(0.95)

x = 1.56 years. ( this will equal 12,000

Round to 2 years it will be less than 12000.

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3 years ago
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6 0
2 years ago
The decimal $0.76$ is equal to the fraction $\frac{4b+19}{6b+11}$, where $b$ is a positive integer. What is the value of $b$?
Vadim26 [7]

Answer:

The value of b is 19.

Step-by-step explanation:

With what the problem states, we have that:

\frac{4b + 19}{6b + 11} = 0.76

Doing cross multiplication

4b + 19 = 0.76(6b + 11)

4b + 19 = 4.56b + 8.36

4.56b - 4n = 19 - 8.36

0.56b = 10.64

b = \frac{10.64}{0.56}

b = 19

The value of b is 19.

3 0
3 years ago
Solve 0=2y−8x+10 for y
qaws [65]

Answer:y

y=4x−5

Step-by-step explanation:

3 0
3 years ago
Please help me in this question
charle [14.2K]
Number defective=4
number of non-defective=total-defective
=20-4
=16
the questions asked for 1 defective
so we choose only 1 defective from 4 defective items
4C1

and for 1 non-defective
we choose only 1 non-defective from 16 non-defective items
16C1

we choose 2 items from 20 items
so 20C2

answer:
probability= [(4C1) * (16C1)] /(20C2)
=32/95

6 0
2 years ago
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