9514 1404 393
Answer:
Step-by-step explanation:
The thrust of the question is to make sure you understand that increasing the y-coordinate of a point will move the point upward, and decreasing it will move the point downward.
That is adding a positive value "k" to x^2 will move the point (x, x^2) to the point (x, x^2+k), which will be above the previous point by k units.
If k is subtracted, instead of added, then the point will be moved downward.
The blanks are supposed to be filled with <u> positive </u>, and <u> negative </u>.
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<em>Comment on the question</em>
The wording of the statement you're completing is a bit odd. If k is negative (-2, for example), this statement is saying the graph is translated down -2 units. It is not. It is translated down |-2| = 2 units. The direction of translation depends on the sign of k. The amount of translation depends on the magnitude of k.
If you thoroughly understand (x, y) coordinates and how they are plotted on a graph, it should be no mystery that changing the y-coordinate will change the vertical position of the graph.
Answer:
Option 3. 71 ft. is the distance between B and top of the hill.
Step-by-step explanation:
Let the height of the hill is h ft and the distance of A from the hill be x ft and distance from B to hill is y.
It is given distance between A and B is 45 ft. ∠BAO = 65° and ∠ABO = 80°.
We have to find the distance of B from the top of the hill.
Now from ΔACO 

From ΔBCO 
h = 5.67x
Now h = 5.67x = 2.14(45-x)
5.67x = 96.3 - 2.14x
2.14x + 5.67x = 96.3
7.81x = 96.3
x = 96.3/7.81 = 12.33 ft
Therefore 


Therefore 71 ft is the distance between B and the top of the hill.
Answer:
2t blocks
Step-by-step explanation:
We measure these distances from Jim's house.
The school is t blocks from Jim's house. Twice that is 2t blocks. Thus, the library is 2t blocks from Jim's house.
Answer:
11.6 miles
Step-by-step explanation:
Given that:
Distance from J2 to J3 = 8.7 miles
Distance between J1 and J2 = 1/3 of J2 toJ3
Hence, distance between J1 and J2 becomes :
1/3 * 8.7 miles = 2.9 miles
Distance from J1 to J3 equals :
(J1 to J2) + (J2 to J3)
2.9 miles + 8.7 miles
= 11.6 miles