Answer:
20%
Step-by-step explanation:
20% of 50 is 10, and they spent 10 hours walking.
Let's solve your equation step-by-step.<span><span>
6<span>(<span>x−1</span>)</span></span>=<span>9<span>(<span>x+2</span>)</span></span></span>
Step 1: Simplify both sides of the equation.<span><span>
6<span>(<span>x−1</span>)</span></span>=<span>9<span>(<span>x+2</span>)</span></span></span><span>
Simplify:</span><span><span><span><span>
(6)</span><span>(x)</span></span>+<span><span>(6)</span><span>(<span>−1</span>)</span></span></span>=<span><span><span>(9)</span><span>(x)</span></span>+<span><span>(9)</span><span>(2)</span></span></span></span>(Distribute)<span><span><span><span>
6x</span>+</span>−6</span>=<span><span>9x</span>+18</span></span><span><span><span>
6x</span>−6</span>=<span><span>9x</span>+18</span></span>
Step 2: Subtract 9x from both sides.<span><span><span><span>
6x</span>−6</span>−<span>9x</span></span>=<span><span><span>9x</span>+18</span>−<span>9x</span></span></span><span><span><span>
−<span>3x</span></span>−6</span>=18</span>
Step 3: Add 6 to both sides.<span><span><span><span>
−<span>3x</span></span>−6</span>+6</span>=<span>18+6</span></span><span><span>
−<span>3x</span></span>=24</span>
Step 4: Divide both sides by -3.<span><span><span>
−<span>3x</span></span><span>−3</span></span>=<span>24<span>−3</span></span></span><span>
x=<span>−8</span></span><span>
Answer: x= -8
-Hope I helped.</span>
Answer:
Step-by-step explanation:
Triangles are similar if their <em>corresponding angles are congruent</em> and <u><em>corresponding sides are proportional</em></u>.
Simple...
you have: (7,-7) and (6,-5)
Using

to find slope--->>>

=-2
m=-2
Using y=mx+b to find the equation of the line-->>(Use any of the coordinates)
(7,-7)
-7=-2(7)+b
-7=-14+b
-7=-14+b
+14 +14
7=b
y=-2x+7Thus, your answer.
Answer:
The standard enthalpy of combustion of ethene gas, , is at . Given the following enthalpies of formation, calculate for .
Step-by-step explanation:
The standard enthalpy of combustion of ethene gas, , is at . Given the following enthalpies of formation, calculate for .