Answer:
Step-by-step explanation:
Given is a system of equations as
We have 5 variables and 3 equations
a) coefficient matrix of this system is
1 -4 0 -1 0\\
0 1 0 -2 0\\
0 0 0 1 2\\
We find that x3 has no coefficient in any of the equations so we can omit x3 and write as equations for 4 variables as
1 -4 -1 0\\
0 1 -2 0\\
0 0 1 2\\
b) Augmented matrix is
1 -4 -1 0\\ 7
0 1 -2 0\\
3
0 0 1 2\\3
c) For row operations to ehelon form
we can do R1+4R2 = R1
We get
1 0 -9 0 \\ 19
0 1 -2 0 \\ 3
0 0 1 2 \\ 3
Now let us do R1 = R1+9R3 and R2 = R2+2R3
1 0 0 0 \\ 46
0 1 0 0 \\ 9
0 0 1 2 \\ 3
d) We find that there are infinite solutions to the system in parametric form, since x4 and x5 are linked with only one equation
e) x1 = 46, x2 = 9, x4+2x5 =3
Or x1 =46, x2 =9, x4 = 3-2x5, x5 = x5 is the parametric solution
By completing the square: x²-8x+19 = (x-4)²-16+19 = (x-4)²+3 so minimum point = (4,3)
By calculus: f'(x) = 2x-8. (minimum point occurs when f'(x)=0 therefore)
2x-8 = 0 means x=4 and the corresponding y value is 3.
The minimum value of this function (y) is 3 and this occurs when x = 4.
Answer:
70%
Step-by-step explanation:
15/20 is simplified to 3/4
Both of these are rational, so wHaT arE yoU tAlkIng aBouT
Answer:
A
Step-by-step explanation:
first lets find the area of the square
A=l*w
12*12=144 m^2
then lets find the are of the circle
A=pi*r^2
A=3.14*(d/2)^2
the diameter of the circle is 12m
A=3.14*(12/2)^2
A=3.14*(6)^2
A=3.14*36
A=113.04 m^2
Now, lets subtract the area of the circle form the area of the square
144-113.04= 30.96 m^2
So, the answer is A