The math test scores of Mrs. Hunter's class are shown below. 48, 56, 68, 72, 72, 78, 78, 80, 82, 84, 88, 88, 88, 90, 94, 98, 100
2 answers:
You might be interested in
We will find the rational zeros of <span>f(x) = 3x^3 -5x^2 - 12x + 20
1) Arrange in descending order: </span><span>f(x) = 3x^3 -5x^2 - 12x + 20
2) write down the factors of the constant term, 20.
1,2, 4, 5, 10, 20 - these could all be the possible values of p.
3) write down the factors of the leading coefficient, 3.
1,3 - these are the possible values of q.
.
4) write down all the possible values of p/q. both positive and negative values must be written down. Simplify
1/1 ; 1/3 ; 2/1 ; 2/3 ; 4/1 ; 4/3 ; 5/1 ; 5/3 ; 10/1 ; 10/3 ; 20/1 ; 20/3
1 ; 0.33 ; 2 ; 0.67 ; 4 ; 1.33 ; 5 ; 1.67 ; 10 ; 3.33 ; 20 ; 6.67
5) use the simplified p/q in both positive and negative values in the synthetic division. Pls. see attachment for my synthetic division.
Based on my computations, </span>a factor of the polynomial f(x) = 3x^3 -5x^2 - 12x + 20 is: x = -1.67 or x = -5/3
IF THESE ARE THE MISSING CHOICES:
<span>A)2x + 1 B)2x - 1 C)3x+5 D)3x - 5.
</span>
MY ANSWER IS: D) 3x - 5.
1) Arrange in descending order: </span><span>f(x) = 3x^3 -5x^2 - 12x + 20
2) write down the factors of the constant term, 20.
1,2, 4, 5, 10, 20 - these could all be the possible values of p.
3) write down the factors of the leading coefficient, 3.
1,3 - these are the possible values of q.
.
4) write down all the possible values of p/q. both positive and negative values must be written down. Simplify
1/1 ; 1/3 ; 2/1 ; 2/3 ; 4/1 ; 4/3 ; 5/1 ; 5/3 ; 10/1 ; 10/3 ; 20/1 ; 20/3
1 ; 0.33 ; 2 ; 0.67 ; 4 ; 1.33 ; 5 ; 1.67 ; 10 ; 3.33 ; 20 ; 6.67
5) use the simplified p/q in both positive and negative values in the synthetic division. Pls. see attachment for my synthetic division.
Based on my computations, </span>a factor of the polynomial f(x) = 3x^3 -5x^2 - 12x + 20 is: x = -1.67 or x = -5/3
IF THESE ARE THE MISSING CHOICES:
<span>A)2x + 1 B)2x - 1 C)3x+5 D)3x - 5.
</span>
MY ANSWER IS: D) 3x - 5.
Answer:
The center require to have a 4.6 inspectors, but this on you decide if you have 4 or 5 inspectors, it may not have 4.6 people working.
So then if you decide to have 5 people their utilization percentage is 83.3%, but if you decide to have 4 people their utilization rate will be 104.17% at the risk of defaulting on demand.
Step-by-step explanation:
1. Define your variables
Demand rate= 50 vehicles per hour
Service rate = 12 vehicles per hour per inspector
Inspectors= a
2. Use the formule of the center´s utilization
U=
0,9=
0,9a=
a=
a= 4.6
3. According to the center´s utilization formula the center require 4,6 inspectors, but approaches 5 because people cannot be divided. With this numbers of inspectors the utilization is:
U=
U=
U= 83,3%
4. Other option that you will be used is that the center require 4 inspectors. With this numbers of inspectors the utilization is:
U=
U=
U= 104,17%