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kow [346]
3 years ago
11

6(x+7)x=9 A.12 B.42 C.96 D.16 Please work out the problem.

Mathematics
1 answer:
marin [14]3 years ago
4 0
X = -\frac{7}{2} + \frac{1}{2}  \sqrt{55} or x = -\frac{7}{2} + -\frac{1}{2} \sqrt{55}
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walt is mixing fruit punch for a party. he combines 1 gallon 2 quarts 3 pints of orange juice, 1 gallon 3 quarts 7 pints of pine
VMariaS [17]

1 gallon = 8 pints. 1 quart = 2 pints.
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Total in pints: 53
Total = 6 gallon 2 quarts 1 pint.
3 0
3 years ago
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Sue washes 25 cars in 5 hours. Find the unit rate in cars per hour.
PilotLPTM [1.2K]

the answer is 5 car / hr.........................................

7 0
2 years ago
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the area of a trapezoid is 36 square inches. The height is 4 inches and one bases twice the length of the other base. What are t
vlada-n [284]
The formula for this is A= \frac{1}{2} ( b_{1} + b_{2} )h.  Filling in accordingly, 36= \frac{1}{2}(x+2x)(4).  This simplifies to 36= \frac{1}{2}(3x)(4) and 36=6x.  Therefore, x = 6 so the bases are 6 and 12.
8 0
3 years ago
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Rewrite 81 as 3 to some power.
NikAS [45]
First, let's find all the factors of 81:

81/3=27
27/3=9
9/3=3
3/1=1

So the factors of 81 are 3,3,3,3, (the numbers by which we divided here).

This means we can write down 81 as 3*3*3*3 or 3^{4} - which is the answer to the question! (three to the power of 4)
5 0
3 years ago
Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav
Furkat [3]

Answer:

  • There is no significant evidence that p1 is different than p2 at 0.01 significance level.
  • 99% confidence interval for p1-p2 is  -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

H_{0}: p1-p2=0

H_{a}: p1-p2≠0

Test statistic can be found using the equation:

z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of the common attribute in population1 (\frac{16}{30} =0.533)
  • p2 is the sample proportion of the common attribute in population2 (\frac{1337}{1900} =0.704)
  • p is the pool proportion of p1 and p2 (\frac{16+1337}{30+1900}=0.701)
  • n1 is the sample size of the people from population1 (30)
  • n2 is the sample size of the people from population2 (1900)

Then z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}} ≈ 2.03

p-value of the test statistic is  0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2±z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}} where

  • z is the z-statistic for the 99% confidence (2.58)

Thus 99% confidence interval is

0.533-0.704±2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}} ≈ -0.171 ±0.237 that is (−0.408, 0.066)

7 0
3 years ago
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