Sqrt(x+4-3)=1
sqrt (x+1) = 1
x+1 = 1^2
x=1-1
x=0
This is how you would get x=0
Hope I helped :)
Let's start with the area of the square

now let's subtract the are of the two half circles.
two half circles are the same as one circle, and we know that the diameter of the circle is 8 (same as the side of a square) so it's radius is 8/2= 4 inches

now we just subtract and our answer is
-3x + 4 > 5
-3x > 5 - 4
-3x > 1
x < 1/-3
x < -1/3