All categories

2 years ago

IF ANSWERD CORRECTLY WILL GIVE BRAINLIEST DO NOT GIVE ME PDFS IF YOU DO I WiLL REPORT YOU

Mathematics

1 answer:

stealth61 [152]2 years ago

3 0

Answer:

https://www.supermarketnews.com/consumer-trends/it-s-new-scene-grocery-shopping-pandemic-changes-behaviors

Step-by-step explanation:

its not a PDF its a website that i think might help you take a look if doesn't help i'll tell you

You might be interested in

Johanna wrote the system of equations. 4 x - 3 y = 1, 5 x + 4 y = 9. If the second equation is multiplied by 4, what should the

polet [3.4K]

Answer:

The first equation must be multiplied by -5 to eliminate x variable by addition

Step-by-step explanation:

4 x - 3 y = 1 (1)

5 x + 4 y = 9 (2)

If the second equation is multiplied by 4

5x+4y=9. ×4

We have,

20x+16y=36 (3)

The first equation should be multiplied by -5 to eliminate x variable by addition

4x-3y=1 × -5

We have

-20x+15y=-5 (4)

Add equation (3) and (4) to eliminate x variable

20x+16y=36

-20x+15y=-5

31y=31

Divide both sides by 31

y=1

Substitute y=1 into equation (1)

4 x - 3 y = 1

4x-3(1)=1

4x-3=1

4x=1+3

4x=4

Divide both sides by 4

x=1

4 0

2 years ago

Read 2 more answers

Two numbers add up to 102 and the first is 8 bigger than the second. What are the two numbers?

lorasvet [3.4K]

The correct numbers are 55 and 47, because they have a difference of 8 and a sum of 102.

4 0

2 years ago

Read 2 more answers

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

Put $(x,y)=(1,1)$

$\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9$

This is true.

So, the point $(1,1)$ satisfies the equation $\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

So, point H is $(1,1)$ .

7 0

2 years ago

You have decided to invest $1000 in a savings bond that pays 4% interest, compounded semi-annually. What will the bond be worth

Evgen [1.6K]

Answer:

$2191.12

Step-by-step explanation:

We are asked to find the value of a bond after 10 years, if you invest $1000 in a savings bond that pays 4% interest, compounded semi-annually.

$FV=C_0\times (1+r)^n$ , where,

$C_0=\text{Initial amount}$ ,

r = Rate of return in decimal form.

n = Number of periods.

Since interest is compounded semi-annually, so 'n' will be 2 times 10 that is 20.

$4\%=\frac{4}{100}=0.04$

$FV=\$1,000\times (1+0.04)^{20}$

$FV=\$1,000\times (1.04)^{20}$

$FV=\$1,000\times 2.1911231430334194$

$FV=\$2191.1231430334194$

$FV\approx \$2191.12$

Therefore, the bond would be $2191.12 worth in 10 years.

3 0

2 years ago

Pls help me complete this

s2008m [1.1K]

Answer:

wow thats alot of "stuff"

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers