Step One
Find the base area of the large hexagon as though the smaller one was not removed.
Area = 3*Sqrt(3) * a^2 /2 where a is the length of one side of the hexagon
a = 5
Area = 3*sqrt(3) * 25/2 = 75 sqrt(3) / 2 of the large hexagon without the smaller one removed.
Step Two
Find the area of the smaller hexagon. In this case a = 4
Area2 = 3*sqrt(3)*16/2 = 3*sqrt(3)*8 = 24 sqrt(3)
Step Three
Find the area of the thick hexagonal area left by the removal of the small hexagon.
Area of the remaining piece = area of large hexagon - area of the small hexagon
Area of the remaining piece = 75 *sqrt(3)/2 - 24*sqrt(3)
Step Four
Find the volume of the results of the area from step 3
Volume = Area * h
h = 18
Volume = (75 * sqrt(3)/2 - 24*sqrt(3))* 18
I'm going to leave you with the job of changing all of this to a decimal answer. I get about 420 cm^3
Answer:
The answer is below
Step-by-step explanation:
The question is not complete, but I would show you how to answer it.
Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, reflection and dilation.
Reflection is the flipping of a figure about an axis. Reflection is a rigid transformation, that is it preserves the shape and size of the figure.
If the distance between Line segment t and line segment r is 5 units and then both line segments are reflected across the y–axis to form line segments t' and r'. The distance between the newly formed line segments t' and r' would still be 5 units
Answer:
Step-by-step explanation:
Using pythagoras theorem,
Answer:
-8y -56
Step-by-step explanation:
Hope this helps! If it does, please mark me brainliest. Thank you! ;)