Question

Find the coordinates of point b on ac such that AB is 1/3 of AC

Answer 1

Answer:

$B = (3, 3)$  

Step-by-step explanation:

From the given graph the coordinates of A are (8,1) and coordinates of C are (-7,7).

The point B lies on the given line AC and divides the line such that $AB = \frac{1}{3}AC$

Thus, it can be said that the point B divides the line in the ratio 1:2.

By, section formula we have:

$B = \bigg(\displaystyle\frac{mx_2 + nx_1}{m+n}, \displaystyle\frac{my_2 + ny_1}{m+n}\bigg)$

where, m:n is the ration in which the line is divided.

Here,

$m:n = 1:2\\(x_1, y_1) = (8,1)\\(x_2, y_2) = (-7,7)$

Putting, all the values, we have,

$B = \bigg(\displaystyle\frac{-7 + 16}{3}, \displaystyle\frac{7 + 2}{3}\bigg)$

$B = (3, 3)$

Answer 2

Answer:

(3,3)

Step-by-step explanation:

8--7=15

15/3 = 5

8-5=3

ordered pair at x=3 is (3,3)