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Anit [1.1K]
3 years ago
12

PLEASE HELP MEEE!!! MATH!! Write a similarity statement of the triangles. Which similarity postulate or theorem proves the trian

gles are similar? What are the congruent angles and/or proportional segments that justify the answer? PLEASE HELP!! picture is attached

Mathematics
1 answer:
bearhunter [10]3 years ago
4 0

Answer:

Step-by-step explanation:

1. The triangles are similar because the sides are proportional and they both hava a right angle.

2. It would be the hypotenuse leg theorem since they are right triangles.

3. The right angle justifies the triangles being similar.

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Please help I will give brainliest!
Burka [1]
Answer: the statement “measure of <4 is 105 degrees” is incorrect.

Explanation: This is because since both angles 1 and 3 are vertical, this means they are both 95. This gives us 190 (95x2). Now we subtract this from 360 which gives us 170. Since angles 2 and 4 are vertical, we divide by 2, which gives us 85, not 105.

Hope this helps! :)
3 0
3 years ago
3 (4x - 2) - 5x = 6 - 7 (-x -2)
Alona [7]

Answer:

0=26

Step-by-step explanation:

Distribute

3(4−2)−5=6−7(−−2)

12−6−5=6-7(-x−2)

Combine like terms

12−6−5=6−7(−−2)

7−6=6−7(−−2)

Distribute

7−6=6−7(−−2)

7−6=6+7x+14

Answer

0=26

4 0
3 years ago
write an equation in standard form with integer coefficients for the line with slope 6/11 going through the point (-1,-6)
yKpoI14uk [10]
If the slope is 6/11 then, in y=mx+b form, m will be 6/11.  When you multiply 6/11 and -1 you get -6/11.  To get the y (-6), you have to add -60/11.  So in, y=mx+b form the equation is y=6/11x+(-60/11).  To make it standard form, you add negative 6/11x to both sides and then multiply by 11 to get rid of the fractions. So therefore the equation would be:

-6x + 11y = - 60
4 0
4 years ago
Graph a line with a slope of 5 that contains the point (-2,4). <br><br>Khan Academy <br>​
weeeeeb [17]

Answer:

Graph the point (-2, 4) and then use rise over run (Up 2 and right 5)

Step-by-step explanation:

y - y1 = m(x - x1)

y - 4 = 2/5(x + 2)

y - 4 = 2/5x + 4/5

y = 2/5x + 24/5

4 0
3 years ago
Suppose a railroad rail is 4 kilometers and it expands on a hot day by 12 centimeters in length. Approximately how many meters w
vredina [299]

Answer:

15.49 metres

Step-by-step explanation:

Given in the question that,

the railroad rail is 4 km before expansion.

To find,

the meters the centre of the rail rise above the​ ground on hot day.

When the railroad expands, it would approximate the forming of an isosceles triangle at the centre of the rail,

with base 4km

and

each isosceles side leg of the triangle is given by

(4 + 12x10^-5) / 2 = 4.00012 / 2 = 2.00006 kilometers

<em>1cm = 10^-2 m = 10^-(2+3) = 10^-5 km</em>

<em />

Taking one half of the isosceles triangle, we have a right triangle with base

base  = 4 / 2 = 2 km

and

hypothenuse = 2.00006 kilometers.

By using the Pythagoras theorem, find the height of the right triangle as formed above.

hypo² = base² + height²

2.00006² - 2² = height²

height = √(2.00006² - 2²)

          = 0.01549km

          = 0.01549 x 10^3 m

          = 15.49m  

Thus, the centre of the rail will rise 15.49 metres above the ground.

6 0
4 years ago
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