Answer:
34
Step-by-step explanation:
x=3+√8
y =3-√8
now,
1/x^2+1/y^2
=1/(3+√8)² + 1/(3-√8)²
= [(3-√8)²+(3+√8)²] / (3+√8)²(3-√8)² [L.C.M = (3+√8)²(3-√8)² ]
=[(3-√8+3+√8)²-2(3-√8)(3+√8) ] / [(3+√8)(3-√8)]²
=[6²-2.(3²-√8² )] / (3²-√8²)² [ a²+ b²=(a+b)²-2ab]
=[36-2(9-8) ]/ (9-8)²
=[36-2.1] / 1²
=34
<h3>
Answer: 8</h3>
Explanation:
The rule says "whatever x is, add 1 to it to get y"
So for instance, if x = 3, then y = x+1 = 3+1 = 4
Now if x = 7, then y = x+1 = 7+1 = 8
Answer:
Silver
Step-by-step explanation:
Find the volume of the coin
<u>Volume of a cylinder</u>
![\textsf{V}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}](https://tex.z-dn.net/?f=%5Ctextsf%7BV%7D%3D%5Csf%20%5Cpi%20r%5E2%20h%20%5Cquad%5Ctextsf%7B%28where%20r%20is%20the%20radius%20and%20h%20is%20the%20height%29%7D)
Given:
Substituting given values into the formula to find the volume:
![\sf \implies V=\pi (1.5)^2(0.25)](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20V%3D%5Cpi%20%281.5%29%5E2%280.25%29)
![\sf \implies V=0.5625 \pi \:cm^3](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20V%3D0.5625%20%5Cpi%20%5C%3Acm%5E3)
Find the density of the coin given it has a measured mass of 18.54 g
<u>Density formula</u>
![\sf \rho=\dfrac{m}{V}](https://tex.z-dn.net/?f=%5Csf%20%5Crho%3D%5Cdfrac%7Bm%7D%7BV%7D)
where:
= density- m = mass
- V = volume
Given:
- m = 18.54 g
![\sf V=0.5625 \pi \:cm^3](https://tex.z-dn.net/?f=%5Csf%20V%3D0.5625%20%5Cpi%20%5C%3Acm%5E3)
Substituting given values into the density formula:
![\implies \sf \rho=\dfrac{18.54}{0.5625 \pi}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20%5Crho%3D%5Cdfrac%7B18.54%7D%7B0.5625%20%5Cpi%7D)
![\implies \sf \rho=10.49149385\:g\:cm^{-3}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20%5Crho%3D10.49149385%5C%3Ag%5C%3Acm%5E%7B-3%7D)
Given:
Therefore, as
the coin is made from silver.
Maybe D ??
Step by step explanation
Answers:
- Incorrect
- Correct
- Correct
==================================================
Explanation:
When applying any kind of reflections, the parallel sides will stay parallel. Check out the diagram below for an example of this.
So PQ stays parallel to RS. Also, QR stays parallel to PS.
The statement "PQ is parallel to PS" is incorrect because the two segments intersect at point P. This letter "P" is found in "PQ" and "PS" to show the common point of intersection. Parallel lines never intersect.