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emmasim [6.3K]
3 years ago
7

Two planes are flying in opposite directions, away from each other, one with the speed of 800 km per hour and the other with the

speed of 840 km per hour. How much farther from each other are the planes getting every hour?
Mathematics
2 answers:
allsm [11]3 years ago
3 0
1640 km every hour is the answer
AveGali [126]3 years ago
3 0
T the average speed of the first plane is 640 km/h, and the speed of the second plane is 640*0.75 = 480 km/h
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Step-by-step explanation:

From kindergarten to sixth grade is seven grades and if for each grade 57 new students get enrolled then 57*7=399 there are 399 students

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Write 6 × 10 -7 in decimal notation.<br><br> 0.0000006<br> 0.00006<br> 600,000<br> 6,000,000
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Question 5 (Multiple Choice Worth 4 points)
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GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

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We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
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Answer:

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