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fgiga [73]
3 years ago
5

An object is dropped from 43 feet below the tip of the pinnacle atop a 527​-ft tall building. The height h of the object after t

seconds is given by the equation h equals negative 16 t squared plus 484. Find how many seconds pass before the object reaches the ground.
Mathematics
2 answers:
Marizza181 [45]3 years ago
5 0

Answer:

5.5 seconds

Step-by-step explanation:

The function that gives the height of the object after t seconds falling is:

h = -16t^2 + 484.

To find the time when the object reaches the ground, we just need to use the value of h = 0 in the equation, and then find the value of t:

0 = -16t^2 + 484.

16t^2 = 484

t^2 = 30.25

t = 5.5 seconds

So the object will reach the ground after 5.5 seconds

daser333 [38]3 years ago
5 0

Answer:

5.5 sec

Step-by-step explanation:

The height h of the object after t seconds is given by the equation

h =- 16 t²+ 484

The height would be zero when the object hits the ground. therefore equating the above equation to zero

0 = - 16 t²+ 484 (solving for t)

16 t²= 484

t² = 484/16

t²= 30.25

taking square root on B.S

t= 5.5 sec

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Damm [24]

hey, I'm not sure about this answer, but I think it's true, sorry

m(2g+5mk)

6 0
3 years ago
Automobile license plates in Massachusetts usually consist of three digits followed by three letters. The first digit is never z
Serga [27]

Answer:

1,58,18,400

Step-by-step explanation:

1st digit can have the values 1-9 (9 distinct values)

2nd digit can have the values 0-9 (10 distinct values)

3rd digit can have the values 0-9 (10 distinct values)

1st letter can have the value A-Z (26 distinct values)

2nd letter can have the value A-Z (26 distinct values)

3rd letter can have the value A-Z (26 distinct values)

Total number of different plates possible = 9*10*10*26*26*26

=1,58,18,400

3 0
3 years ago
Ignoring leap days, the days of the year can be numbered 1 to 365. Assume that birthdays are equally likely to fall on any day o
faust18 [17]

Answer:

Follows are the solution to the given question:

Step-by-step explanation:

They can count the days of the year 1 to 365. The random project consists of drawing a sample of n objects from D where elements are n people's birth in a group but instead, D = {1,....365}. And then there's the issue.

S=365^n

This because the list of future birthdays of n people was its test point; therefore m points will be in the sequence so each point contains 365 distinct outcomes. The probability function P for \Omega is that any event is likely to happen in 365 days.

P(x)=\frac{1}{365^{n}}

if x is between 1 and 365 as well as the occurrence is just all similarly possible

In point i:

That somebody mentions their birthday throughout the party

Guess I was born on day b. Therefore the consequence of "x is in A" is "b is now in the series of x," which is to say, b = bk for some amount k approximately 1 and n.

In point ii:

Any 2 persons share the same birthday at this party". A result x is in B" means which "two of entries in x are same." This means that perhaps the outcome x is in B if or only if bj = bk is in B of two numbers j, and k of 1, of two. , no, n.

In point iii:

Many three students share the same birthday with both the party. The consequence is x at the level of C only when bj = bk = bl at three (different) indices, j, k, l, 1. , no, n.

6 0
3 years ago
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Nezavi [6.7K]

Answer:

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Step-by-step explanation:

1- Determine the sign

2- Combine like terms

5 0
3 years ago
Identify the problem with the following study. A local newspaper published the results of a study that claimed "482 people use t
natita [175]

Answer:

well, only 87 people were asked. How did they get 482?

also, they should have asked the people in the library.

8 0
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