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3 years ago

Never mind this question. I reorganized it and put it out there to be answered.

Mathematics

1 answer:

alukav5142 [94]3 years ago

4 0

Ok glad that you got an answer

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What are the correct answers and why? Simple and concise explanation please!!!

dezoksy [38]

Answer:

$\large\boxed{-\bigg[(x-3)^2+2x\bigg]+1}\\\\\boxed{-x^2+4x-8}$

Step-by-step explanation:

$(g\ \circ\ f)(x)=g\bigg(f(x)\bigg)$

$f(x)=(x-3)^2+2x\\\\g(x)=-x+1\\\\g\ \circ\ f\to\text{put f(x) instead of x in the function g(x)}:\\\\(g\ \circ\ f)(x)=-\bigg[\underbrace{(x-3)^2+2x}_{x}\bigg]+1$

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$-\bigg[(x-3)^2+2x\bigg]+1=-(x-3)^2-2x+1\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=-(x^2-(2)(x)(3)+3^2)-2x+1=-(x^2-6x+9)-2x+1\\\\=-x^2-(-6x)-9-2x+1=-x^2+6x-9-2x+1\\\\\text{combine like terms}\\\\=-x^2+(6x-2x)+(-9+1)=-x^2+4x-8$

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$-x^2+4x-8=-x^2+4x-2^2+2^2-8=-(x^2-4x+2^2)+4-8\\\\=-(\underbrace{x^2-(2)(x)(2)+2^2}_{(a-b)^2=a^2-2ab+b^2})-4=-(x-2)^2-4=-(x+1-3)^2-4$

$In\ (-x+1-3)^2+2x,\ x^2\ will\ be\ positive.\\In\ (-x+1-3)^2+2(-x+1),\ x^2\ will\ be\ positive.$

6 0

2 years ago

Read 2 more answers

What is the constant of proportionality equation for this graph?

kodGreya [7K]

Don’t know please help me get an A+

3 0

2 years ago

Read 2 more answers

Help giving 13 ptsss

amm1812

0, 12, 36, 108
just plug n (1,2,3,4) into the equation and that’s your answer.

6 0

3 years ago

2m-8-m+10 solve it.

Olin [163]

Answer:

m+2

Step-by-step explanation:

Collect like terms

m-8+10

Calculate the term

x+2

Hope this helpsʕ•ᴥ•ʔ

4 0

3 years ago

A: What are the solutions to the quadratic equation x^2+9=0?

Nataliya [291]

Answer:

Part A)

x=-3i

x=3i

Part B)

(x+3i)(x-3i)

Step-by-step explanation:

Given:

Part A)

x^2+9=0

x^2=-9

x= √-9

x=√-1 *√9

x=± i *3

x=±3i

Part B)

x^2+9=0

x^2 - (-9)=0

x2-(3i)^2=0

(x-3i)(x+3i)=0 !

3 0

3 years ago