Margin of error, e = Z*SD/Sqrt (N), where N = Sample population
Assuming a 95% confidence interval and substituting all the values;
At 95% confidence, Z = 1.96
Therefore,
0.23 = 1.96*1.9/Sqrt (N)
Sqrt (N) = 1.96*1.9/0.23
N = (1.96*1.9/0.23)^2 = 262.16 ≈ 263
Minimum sample size required is 263 students.
Answer:
real numbers
Step-by-step explanation:
Answer:
Step-by-step explanation:
Show the question i cant really see
Answer:
90
Step-by-step explanation:
0.9 multiplied by 100 to turn it into a percentage is 90.
