(50 points really need help on this it's the last question)

Mathematics

2 answers:

larisa86 [58]2 years ago

8 0

Answer:

Pretty sure it's C

Step-by-step explanation:

trUst mE

erik [133]2 years ago

8 0

A,C,E

Step-by-step explanation:

I got it right on my test

You might be interested in

Select all of the coefficients in the expression.

WARRIOR [948]

12, 2, 5, 4, 7
The coefficients are the numbers that are in front of the letters

7 0

3 years ago

Read 2 more answers

You have two nickels three dimes and a quarter. Using at least one of each coin, how many different amounts of money can you mak

Slav-nsk [51]

2 nickels (5 cents each)
3 dimes (10 cents each)
1 quarter (25 cents)

1 nickel, 1 dime, 1 quarter
5 + 10 + 25 = 40

2 nickels, 1 dime, 1 quarter
5(2) + 10 + 25 = 45

1 nickel, 2 dimes, 1 quarter
5 + 10(2) + 25 = 50

1 nickel, 3 dimes, 1 quarter
5 + 10(3) + 25 = 60

2 nickels, 2 dimes, 1 quarter
5(2) + 10(2) + 25 = 55

2 nickels, 3 dimes, 1 quarter
5(2) + 10(3) + 25 = 65

You can make 6 different amounts.
You could also find this by multiplying however many coins you have all together.
2 * 3 * 1 = 6

6 0

2 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$