What is 2400 divided by 15

(30r+4)(3r+7) FOIL <br> how do i solve this problem

Alex

First you do parenthesis, then you add and divide to get those variables by themselves, soon you will have the answer to your problem Hope this helped :) and I hope it wasn't a fishy answer>)))'>:(

8 0

4 years ago

Your school’s band decides to sell cookie dough kits to raise money for a spring field trip. There is a Family Times Cookie Doug

nikitadnepr [17]

Answer:

Step-by-step explanation:

let the Cookie Dough kit be x

and Baker’s Delight kit be y

cost of Cookie Dough kit= $7

cost of Baker’s Delight= $15

so

x+y=220------------1

7x+15y=2100------2

solve for x and y we have

multiply eqn 1 by 7 and subtract

7x+7y=1540---------3

- 7x+15y=2100-------2

0x-8y=-560

8y=560

divide both sides by 8 we have

y=560/8

y=70

put y=70 in eqn 1 we have

x+70=220

x=220-70

x=150

x=220-70

x=150

A. How many of each type of kit should your band purchase to raise the most money

Cookie Dough kit= 150

Baker’s Delight= 70

B. What is the most money that your band can raise?

Cookie Dough kit profit= selling price-cost price= 12-7= $5

Baker’s Delight profit= selling price-cost price= 25-15= $10

Amount made for Cookie Dough = 150*5=$750

Amount made for Baker’s Delight = 70*10=$700

total= 750+700= $1450

3 0

3 years ago

Nirmala graphed the relationship between the duration (in hours) of using an oil lamp and the volume (in milliliters) of oil rem

mariarad [96]

Answer:

Nirmala can use the lamp for 31.66 hours before it runs out of oil.

Step-by-step explanation:

From the graph,

Take any two points, let say

(15, 25)

(25, 10)

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(15,\:25\right),\:\left(x_2,\:y_2\right)=\left(25,\:10\right)$

$m=\frac{10-25}{25-15}$

$m=-\frac{3}{2}$

The equation of line in slope-intercept form

$y = mx + b$

Putting $m=-\frac{3}{2}$ and any point, let say (25, 10), to find the y-intercept 'b'

$10=-\frac{3}{2}\left(25\right)+b$

$-\frac{3}{2}\left(25\right)+b=10$

$-\frac{75}{2}+b=10$

$\mathrm{Add\:}\frac{75}{2}\mathrm{\:to\:both\:sides}$

$-\frac{75}{2}+b+\frac{75}{2}=10+\frac{75}{2}$

$b=\frac{95}{2}$

$b=47.5$

So the equation of line will be:

$y = mx + b$

$y=-\frac{3}{2}x+47.5$

In order to find how long Nirmala can use the lamp before it runs out of oil, we need to find x-intercept which can be obtained by putting y = 0, and solve for x, as duration lies on x-axis.

so

$y=-\frac{3}{2}x+47.5$

Putting y = 0

$0=-\frac{3}{2}x+47.5$

$-\frac{3}{2}x+47.5=0$

$-\frac{3}{2}x=-47.5$

$\mathrm{Multiply\:both\:sides\:by\:}2$

$2\left(-\frac{3}{2}x\right)=2\left(-47.5\right)$

$-3x=-95$

$\mathrm{Divide\:both\:sides\:by\:}-3$

$\frac{-3x}{-3}=\frac{-95}{-3}$

$x=\frac{95}{3}$

$x=31.66$

Therefore, Nirmala can use the lamp for 31.66 hours before it runs out of oil.

4 0

3 years ago

Read 2 more answers

A water tank holds 621 gallons but is leaking at a rate of 4 gallons per week. A second water tank holds 828 gallons but is leak

hram777 [196]

Answer:

69 weeks

Step-by-step explanation:

Let the number of weeks be x.

The first tank holds 621 gallons is leaking at a rate of 4 gallons per week. This means that after x weeks, the amount of water in the tank is:

621 - 4x

The second tank holds 828 gallons is leaking at a rate of 7 gallons per week. This means that after x weeks, the amount of water in the tank is:

828 - 7x

After a certain amount of weeks, the amount of water in both tanks is the same. That means that:

621 - 4x = 828 - 7x

=> 7x - 4x = 828 - 621

3x = 207

x = 207 / 3 = 69

This means that the amount of water in the tank will be the same after 69 weeks.

8 0

4 years ago

How do you figure out what type of solution it is when their are 2 ordered pairs

iris [78.8K]

Answer:

To figure out if an ordered pair is a solution to an equation, you could perform a test. Identify the x-value in the ordered pair and plug it into the equation. When you simplify, if the y-value you get is the same as the y-value in the ordered pair, then that ordered pair is indeed a solution to the equation.

Step-by-step explanation:

4 0

3 years ago