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Pavlova-9 [17]
3 years ago
11

At the battle of bunker hill approximately 2400 colonial army troops clashed with 3000 British army troops what is the ratio of

the number of British army troops to the number of colonial army troops ?
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
7 0

Answer:3000:2400

Step-by-step explanation:

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Solve the following problems. Remember that all reasoning must be explained, and all steps of math work must be shown!
iris [78.8K]

Answer to Question 1:

<OGE (also m˚) = 19˚

Step-by-step explanation:

We know that all the angles in a triangle add up to 180˚.

<u>Given:</u>

<EGO = 71˚

<OEG = 90˚ (the angle forms a right angle because line EG is perpendicular to point O)

<u>To Solve:</u>

⇒ Since we know two angles, we should know the third; and they all add up to 180˚. This can be written as:

71˚ + 90˚ + <OGE = 180˚

⇒ Solve for <OGE by simplifying:

161˚ + <OGE = 180˚

⇒ Subtract 161˚ from both sides to get:

161˚ − 161˚ + <OGE = 180˚ − 161˚

⇒ Isolate <OGE:

<OGE = 19˚

<u>Answer:</u> <OGE (also m˚) = 19˚

Answer:

<OAC (also x˚) = 50˚

<OCB (also y˚) = 90˚

Step-by-step explanation:

–<u>How to solve for <OCB (also y˚)</u>

Just by looking, you can already tell that <OCB equals 90˚ because it forms a right angle.

<u>Answer:</u> <OCB (also y˚) = 90˚

–<u>How to solve for <OAC (also x˚)</u>

<u>Given (and what we can already know):</u>

<AOC = 40˚

<OCA = 90˚

⇒ Reason: Line AB is a straight line and a straight line equals 180˚. We already know on side of the line because <OCB is 90˚, and so the other side, <OCA, should also be 90˚, since the both sides that make up the straight line equal 180˚ (90˚ + 90˚ = 180˚). You can also tell that <OCA forms a right angle in the triangle because line AB is perpendicular to point O, and right angles are 90˚.

<u>To Solve:</u>

⇒ Since we know two angles in the triangle, we should know the third; and they all add up to 180˚. This can be written as:

40˚ + 90˚ + <OAC = 180˚

⇒ Solve for <OAC by simplifying:

130˚ + <OAC = 180˚

⇒ Subtract 130˚ from both sides to get:

130˚ − 130˚ + <OAC = 180˚ − 130˚

⇒ Isolate <OAC:

<OAC = 50˚

<u>Answer:</u> <OAC (also x˚) = 50˚

I hope you understand and that this helps with your question! :)

3 0
3 years ago
How do you do...<br> cos2x-sin2x=1-2sin2x
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sin (2 \alpha) =2\cdot sin  \alpha \cdot cos  \alpha \\cos(2 \alpha )=1-2sin^2  \alpha \\-------------------- \\cos2x-sin2x=1-2sin2x\\cos2x+sin2x=1\\1-2sin^2x+2sinx\cdot cosx=1\\-2sinx(sin x-cosx)=0\\ -2sinx=0\ \ \ \ or\ \ \ \ sinx-cosx=0\\\\1)\ -2sinx=0\ \ \Leftrightarrow\ \ sinx=0\ \ \Leftrightarrow\ \ x_1=k \pi \ \ and\ \ k\in I\\2)\ \ sinx-cosx=0\ \ \Leftrightarrow\ \ sinx=cosx\ /:cosx\ \ \ \ \ \wedge\ \ \ \  cos x \neq 0\\tanx=1\ \ \Leftrightarrow\ \ x_2= \frac{ \pi }{4} +k \pi \ \ and\ \ k\in I
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3 years ago
What is the answer to this please help
lora16 [44]

Answer:

A = 140

Step-by-step explanation:

Area of a triangle:

A = 1/2bh

Given:

b = 20

h = 14

Work:

A = 1/2bh

A = 1/2(20)(14)

A = 10(14)

A = 140

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