Answer:
2(15p+1)
Step-by-step explanation:
hope this helps
Answer:
x+6<12
Step-by-step explanation:
Since it is going left from 6, we know that x must be less than 6
(if u need me to explain more I can)
Complete question is;
How many 10 - digit numbers are there, such that the sum of the digits is divisible by 2?
Answer:
There are 4500000000 ten digit numbers whose sum is divisible by 2.
Step-by-step explanation:
Since we are dealing with 10 digit numbers, the first 10 digit number whose sum is divisible by 2 is; 1000000001.
While the last 10 digit number whose sum is divisible by 2 is 9999999999.
Now,to find how many 10 digit numbers whose sum are divisible by 2, we will simply divide the difference of both numbers by 2 and then add 1 to the answer. This is because subtracting the minimum from the maximum gives us the number of 10 digit numbers we have. Then dividing by 2 gives the number of ten digit numbers with sum divisible by 2 in between. Then adding 1 to the result to cover the number not included gives;
((9999999999 - 1000000001)/2) + 1 = 4500000000
Answer:
(x + 1/2)^2 = 289/4
Step-by-step explanation:
x^2+x-72=0
Write like this:
(x + ___)^2 = ___
put 72 on other side
x^2 + x = 72
x^ + x + (1/4) = 72 + (1/4)
(x + 1/2)^2 = 289/4
x + (1/2) = 17/2
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