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Kitty [74]
4 years ago
6

Which is true about the completely simplified difference of the polynomials a3b + 9a2b2 − 4ab5 and a3b − 3a2b2 + ab5? The differ

ence is a binomial with a degree of 5.
The difference is a binomial with a degree of 6.

The difference is a trinomial with a degree of 5.

The difference is a trinomial with a degree of 6.
Mathematics
2 answers:
tamaranim1 [39]4 years ago
6 0
<span>Let be A =a3b +9a2b2-4ab5, and B=a3b-3a2b2+ab5,so the difference can be defined as A - B =a3b +9a2b2-4ab5 -(a3b-3a2b2+ab5), when there is negative sign in front of the parathesis, all the inside signs must change: that is as follow: A- B= a3b +9a2b2-4ab5 - a3b + 3a2b2 - ab5= a3b-a3b +9a2b2+3a2b2-4ab5- ab5= 12a2b2 -5ab5, the fist term has 2+2=4, as a degree,the second term has 1 +5 =6, so the true answer : The difference is a binomial with a degree of 6</span>
Digiron [165]4 years ago
5 0
Using the inverse additional property, a3b and a3b cancel out, positive 9a2b2 and 3a2b2 add together to get 12a2b2, and negative -4ab5 and -ab5 add together to -5ab5. Thus. your simplified equation is 12 a2b2 - 5ab5. 

It is a binomial with a degree of 6. 

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