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Afina-wow [57]
3 years ago
10

Solve the quadratic equation for x. What is the product when the roots are multiplied? (x + 2)2 = 1

Mathematics
2 answers:
tekilochka [14]3 years ago
4 0

Regroup terms

2(x + 2) = 1

Divided both sides by 2

x + 2 = 1/2

Subtract 2 from both sides

x = 1/2 - 2

Simplify 1/2 - 2 to -3/2

<u>x = -3/2</u>

sveticcg [70]3 years ago
4 0

Answer:

x = -2 or 0; Product of roots = 0.  

Step-by-step explanation:

Product of roots:

        (x + 1)² = 1

x² + 2x + 1    = 1

x²  +2x         = 0

The standard form of a quadratic is a² + bx + c = 0.

In your equation, a = 1; b = 2; c = 0

Even without solving the equation, we know that the product of the roots is zero, because

Product of roots = c/a =0/1 = 0

Solution:

Factor the quadratic                x(x +2) = 0

Use zero product property     x = 0     x + 2 =  0

                                                              x       = -2

The roots are x = 0 and x = -2.

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Answer:

Using it's concept, it is found that there is a 8.3% probability of flipping a head AND rolling a 3.

4 0
2 years ago
You are making identical gift bags using 12 crayons and 28 bottles of bubbles. What is the greatest number of gift bags you can
const2013 [10]
Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.

Hope I could help.
4 0
2 years ago
A formula for a function y=f(x) is f(x)=x^2-10x,xless than or equal 5. Find f^-1(x) and indentify the domain and range of f^-1(x
evablogger [386]
F(x) =x² - 10x,  f⁻¹(x) =?

1st find the missing square of x²-10x, ==> (x-5)² - 25

y= (x-5)² - 25; replace x by y and v0ce versa: x= (y-5)² -25
or
(y-5)² = x+25
y-5 = √(x+25) and y = √(x+25) -5

Domain = {x∈R: X>= 25} AND Range ={y∈R: y>= 5}

6 0
3 years ago
Solve the equation graphically: √ x = - x.
Nikolay [14]
Sqrt[x] = -x   
x= x ^ 2  
x - x^2 = 0
-x(x-1)=0
x(x-1)=0
x = 1 or x = 0
sqrt 1 isn not equal to 0

x= 0

6 0
3 years ago
What is the solution to the system of equations below?
Vanyuwa [196]

Answer:

A. (–8, 2)

Step-by-step explanation:

(1)       y =  ½x + 6  

(2)       y = -¾x –  4     Set (1) = (2)  

½x +   6 = -¾x –  4     Multiply each side by 4

2x  + 24 = -3x – 16     Add 16 to each side

2x  + 40 = -3x              Subtract 2x from each side  

        40 = -5x              Divide each side by -5

(3)       x = -8                 Substitute (2) into (1)

          y = ½(-8)  +6

             = -4 + 6

             =  2

The solution to the system of equations is (-8 ,2).

You can see the graphs of the two functions in the figure below. The two lines intersect at (-8, 2).

Check:

2 = ½(-8) + 6     2 = -¾(-8) - 4

2 = -4 +6           2 = 6 - 4

2 = 2                 2 = 2

8 0
3 years ago
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