Answer:
Using it's concept, it is found that there is a 8.3% probability of flipping a head AND rolling a 3.
Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.
Hope I could help.
F(x) =x² - 10x, f⁻¹(x) =?
1st find the missing square of x²-10x, ==> (x-5)² - 25
y= (x-5)² - 25; replace x by y and v0ce versa: x= (y-5)² -25
or
(y-5)² = x+25
y-5 = √(x+25) and y = √(x+25) -5
Domain = {x∈R: X>= 25} AND Range ={y∈R: y>= 5}
Sqrt[x] = -x
x= x ^ 2
x - x^2 = 0
-x(x-1)=0
x(x-1)=0
x = 1 or x = 0
sqrt 1 isn not equal to 0
x= 0
Answer:
A. (–8, 2)
Step-by-step explanation:
(1) y = ½x + 6
(2) y = -¾x – 4 Set (1) = (2)
½x + 6 = -¾x – 4 Multiply each side by 4
2x + 24 = -3x – 16 Add 16 to each side
2x + 40 = -3x Subtract 2x from each side
40 = -5x Divide each side by -5
(3) x = -8 Substitute (2) into (1)
y = ½(-8) +6
= -4 + 6
= 2
The solution to the system of equations is (-8 ,2).
You can see the graphs of the two functions in the figure below. The two lines intersect at (-8, 2).
Check:
2 = ½(-8) + 6 2 = -¾(-8) - 4
2 = -4 +6 2 = 6 - 4
2 = 2 2 = 2