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lyudmila [28]
2 years ago
8

After swimming to a depth of 55 feet below the surface of

Mathematics
1 answer:
Lerok [7]2 years ago
3 0

Answer:

Your answer to this question is B. The equation is -55 + 30 = -25. The fish is 25 feet below the water's surface.

Step-by-step explanation:

Hope this helps!

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U.S. soybeans average 39% protein. A bushel of soybeans weighs 60 lbs. How many pounds of protein are in a bushel? A 120-acre fi
Salsk061 [2.6K]

Answer:

Step-by-step explanation:

7 0
2 years ago
HELP ME PLEASE ITS A TEST
alex41 [277]
F(x) is the same as y. so you’d choose two coordinates and do y2-y1 over x2-x1. id recommend doing that with whole numbers, no decimals. by doing that you get your slope.
7 0
3 years ago
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Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the
sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let y(t) be the depth of water in the barrel at time t,  where y is measured in inches and t in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

                                                 \frac{dy}{dt}=-k\sqrt{y}

where k is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by \frac{1}{\sqrt{y}}

\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k

Multiply by dt

\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt

Take integral

\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt

Integrate

2\sqrt{y}=-kt+C

Isolate y

y(t)=(\frac{C}{2} -\frac{k}{2}t)^2

We know that the water level starts at 36, this means y(0)=36. We use this information to find the value of C.

36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12

y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2

At t = 1, y = 34

34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}

So our formula for the depth of water in the barrel is

y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\

To find the time, t, at which all the water leaks out of the barrel, we solve the equation

\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0
3 years ago
Home CoworkHelper
9966 [12]

Answer:

See below.

Step-by-step explanation:

PROBLEM A

The formula for the volume of a cylinder is

V = πr²h, where πr² is the area of the base.

V = area of base x height

  1. Choose any four numbers that are less than 10 for the height.
  2. Then, substitute into the formula and isolate "r". 10 = πr²h
  3. Double "r" to find the diameter.
  4. The area of the base is found (bolded) while you solve πr².

*I will use the calculator button for pi (π)

<u>Cylinder A: </u><u>h = 1</u>

10 = πr²h

10 = πr²(1)

10 = πr²                       Area of the base is 10m².

r = √ (10/π)

r = 1.78                        Radius is 1.78m.

d = 2r = 1.78*2 = 3.56                     Diameter is 3.56m.

<u>Cylinder B: </u><u>h = 2</u>

10 = πr²h

10 = πr²(2)

5 = πr²                       Area of the base is 5m².

r = √ (5/π)

r = 1.26                      Radius is 1.26m.

d = 2r = 1.26*2 = 2.52                     Diameter is 2.52m.

<u>Cylinder C: </u><u>h = 4</u>

10 = πr²h

10 = πr²(4)

2.5 = πr²                       Area of the base is 2.5m².

r = √ (2.5/π)

r = 0.89                        Radius is 0.89m.

d = 2r = 0.89*2 = 1.78                     Diameter is 1.78m.

<u>Cylinder D: </u><u>h = 5</u>

10 = πr²h

10 = πr²(5)

2 = πr²                       Area of the base is 2m².

r = √ (2/π)

r = 0.80                     Radius is 0.8m.

d = 2r = 0.80*2 = 1.6                     Diameter is 1.6m.

The answers are reasonable if the answer is close to 10 when you substitute the rounded numbers back into the formula and solve.

There are infinite possibilities because any numbers when used in the formula equates to 10 are possible. The height/radius can be any decimal number, which would make the other dimensions change.

PROBLEM B

Follow similar steps if you know the diameter of a cylinder. Use the same formula V = πr²h.

We need the radius, which is half the diameter. r = d/2 = 10/2 = 5

  1. Choose a random number for volume that divides easily by 25.
  2. Substitute "V" and "r²" (r² = 25).
  3. Isolate "h".
  4. The area of the base is 78.54 cm² every time (A = πr²).

<u>Cylinder A: </u><u>V = 100</u>

100 = π25h

4 = πh

h = 1.27                      The height is 1.27m.

<u>Cylinder B: </u><u>V = 200</u>

200 = π25h

8 = πh

h = 2.55                      The height is 2.55m.

<u>Cylinder C: </u><u>V = 75</u>

75 = π25h

3 = πh

h = 0.95                      The height is 0.95m.

<u>Cylinder D: </u><u>V = 125</u>

125 = π25h

5 = πh

h = 1.59                      The height is 1.59m.

The answers are reasonable if I can substitute two rounded values into the formula and get a number close to the third. The height is also a decimal number which occurs because of pi.

6 0
3 years ago
What is the measure of x?<br>Angles are not necessarily drawn to scale.​
Irina18 [472]

Answer:

139°

Step-by-step explanation:

these angles are supplementary angles, meaning that when added together, they equal 180°

so you just need to subtract 41 from 180 which gets you 139.

3 0
3 years ago
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