All categories

2 years ago

After swimming to a depth of 55 feet below the surface of

Mathematics

1 answer:

Lerok [7]2 years ago

3 0

Answer:

Your answer to this question is B. The equation is -55 + 30 = -25. The fish is 25 feet below the water's surface.

Step-by-step explanation:

Hope this helps!

You might be interested in

Determine whether the variable is qualitative or quantitative. Is the variable qualitative or quantitative? favorite rock group

kirza4 [7]

Answer:

qualitative

Step-by-step explanation:

Favorite rock group is the qualitative variable because it shows an attribute. It does not depict a quantity or numbers. The favorite rock group will perform and show their ability to deliver music articles so it is showing quality not quantity. It is an attribute.

Variable is defined as the characteristic being studied so it is a qualitative variable meaning it is showing quality of the characteristic.

6 0

3 years ago

Round off 6 337 927 to 3 significant figures

Marianna [84]

Answer:6340000

Step-by-step explanation:

6 0

2 years ago

The coordinates of a point on a coordinate grid are (−2, 6). The point is reflected across the x-axis to obtain a new point. The

Juliette [100K]

The reflected coordinate will be (-2,-6)

3 0

3 years ago

Read 2 more answers

Jessie has some nickels, dimes, and quarters in her bank. The number of coins is 30. The expression 0.05n + 0.10d + 0.25q repres

goldfiish [28.3K]

Answer:

n = 12 nickels

d = 11 dimes

q = 7 quarters

Step-by-step explanation:

.05n + .1d + .25q = 3.45

n + d + q = 30

n = q + 5

n = 12

d = 11

q = 7

8 0

3 years ago

Yuto and Riko went for a bike ride on the same path. When Riko left their house, Yuto was 5.25 miles along the path. If Yuto’s a

Nimfa-mama [501]

Answer:

Step-by-step explanation:

When Riko left his house, Yuto was 5.25 miles along the path.

Average speed of Riko = 0.35 miles per minute

Average speed of Yuto = 0.25 miles per minute

First we will calculate the time in which Riko will catch Yuto on the track.

Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto

= 0.35 - 0.25

= 0.10 miles per minute

Now we this relative velocity tells that Riko is moving and Yuto is in static position.

By the formula,

Average speed = $\frac{Distance}{Time}$

0.10 = $\frac{5.25}{t}$

t = $\frac{5.25}{0.1}$

t = 52.5 minutes

Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.

So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5

Here time can not be less than zero because time can not be with negative notation. It will always start from 0.

3 0

4 years ago

Read 2 more answers