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juin [17]
3 years ago
6

What is the solution to the system of equations below?

Mathematics
1 answer:
Vanyuwa [196]3 years ago
8 0

Answer:

A. (–8, 2)

Step-by-step explanation:

(1)       y =  ½x + 6  

(2)       y = -¾x –  4     Set (1) = (2)  

½x +   6 = -¾x –  4     Multiply each side by 4

2x  + 24 = -3x – 16     Add 16 to each side

2x  + 40 = -3x              Subtract 2x from each side  

        40 = -5x              Divide each side by -5

(3)       x = -8                 Substitute (2) into (1)

          y = ½(-8)  +6

             = -4 + 6

             =  2

The solution to the system of equations is (-8 ,2).

You can see the graphs of the two functions in the figure below. The two lines intersect at (-8, 2).

Check:

2 = ½(-8) + 6     2 = -¾(-8) - 4

2 = -4 +6           2 = 6 - 4

2 = 2                 2 = 2

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7 0
4 years ago
Find the perimeter of OQR if OQ=6.5.<br> A.<br> 6.1<br> B.<br> 12.2<br> C.<br> 13<br> D.<br> 19.1
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ANSWER


The correct answer is 19.1


EXPLANATION


The perimeter of triangle OQR is the sum of the distance around the triangle.



Thus,


Perimeter=|OQ|+|OR|+|RQ|



We can observe that two of the angles are equal.



The angles that are equal measures 62° each.



Therefore triangle OQR is an isosceles triangle. This means that



|OQ|=6.5=|OR|



Hence,



Perimeter=6.5+6.5+6.1




Perimeter=19.1 units.


3 0
3 years ago
Read 2 more answers
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