Question

Whats the vertex at of y-13=2(x+4)^2

Answer 1

The vertex form:
$y=a(x-h)^2+k$
(h,k) - the coordinates of the vertex

$y-13=2(x+4)^2 \\ y=2(x+4)^2+13 \\ y=2(x-(-4))^2+13 \\ \\ h=-4 \\ k=13$

The coordinates of the vertex are (-4,13).

Answer 2

The coordinates of the vertex are (-4,13).