Whats the vertex at of y-13=2(x+4)^2

2 answers:

7 0

The vertex form:
$y=a(x-h)^2+k$
(h,k) - the coordinates of the vertex

$y-13=2(x+4)^2 \\
y=2(x+4)^2+13 \\
y=2(x-(-4))^2+13 \\ \\
h=-4 \\ k=13$

The coordinates of the vertex are (-4,13).

sashaice [31]2 years ago

4 0

The coordinates of the vertex are (-4,13).

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