Answer:
there are several methods to "solve a quadratic"
you can look them all up...
Graphing, factoring, completing the square, taking roots, quadratic formula are the common methods....
given the way you are asking the question I think that you are supposed to use the quadratic formula ..
please look at the image of the formula and
realize that you problem has
a=-1
b=2
c=6
just plug in those numbers into the formula and you will get the results in the "answer"
NOTE is written as ix ( )
Step-by-step explanation:
x= <u>-2+√ (2)²- (4)(-1)(-6) </u>
(2)(-1)
and
x= <u>-2-√ (2)²- (4)(-1)(-6) </u>
(2)(-1)
Answer:
and 4
Step-by-step explanation:
To simplify like surds, add/ subtract the coefficients.
(a)
(6 - 5)
= (1)
=
(b)
( 1 + 3)
= (4)
= 4
Step-by-step explanation:
we first square both sides to eliminate the square root brackets..
(√(m(y+n)/y)²= p²
m(y+n)/y = p²
(my +mn)/y =p²
so we multiply both sides by y to eliminate the denominator,
(my+mn)/y*y =p²*y
my+mn = p²y
collecting like terms,we have:
mn= p²y-my
so we seperate the y on the right hand side from the rest to have
mn = y(p²-m)
so divided both sides by the value in the bracket on the right hand side we have..
mn/(p²-m)=y(p²-m)/(p²-m)
so we have,
y= mn/(p²-m)