Which decimal is less than 2.5?

denpristay [2]

Answer:

Step-by-step explanation:

Given the ratio of the profit, cost of materials and labour in the production of

an article to be 5:7:13 respectively, total ratio = 5+7+13 = 25

If the cost of labour is x, the cost of material will be 840+x (since the cost of materials is Le 840 more than that of labour) .

Let the total cost of producing the article be y.

Cost of labour = 13/25 * y = x

Cost of labour = 13y/25 = x.................... 1

Cost of material = 7/25*y = 840+x

Cost of material = 7y/25 = 840+x ..................... 2

From 1, 13y = 25x

x = 13y/25 ................... 3

Substituting equation 3 into 2:

7y/25 = 840+x

7y/25 = 840+13y/25

collect the like terms:

7y/25 - 13y/25 = 840

-6y/25 = 840

-6y = 25*840

y = 25*840/6

y = 3,500

Hence the total cost of producing the article is 3500

4 0

3 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

Andrew adds two numbers. Each addend has seven digits. The sum has eight digits. What digit is in the ten millions place in the

tatuchka [14]

Answer:

5,000,000 and 6,000,000

Step-by-step explanation:

5,000,000 and 6,000,000 is 11,000,000

or 5,000,000 and 5,000,000 is 10,000,000

and the 1 is in the ten millions place in the sum

4 0

3 years ago

Interest rate fixed at 6%, n = 26 payments per year, for payment

sergiy2304 [10]

Answer:

hi the anser might be 600$

Step-by-step explanation:

8 0

3 years ago

Can I see how long division works on these? pls no sketchy links

alexandr1967 [171]

Answer:

Step-by-step explanation:

11) First write in decreasing exponential terms and fill in blanks with zeros.

Our goal is to eliminate all term in the dividend by subtraction

________________

2v - 2 | 2v³ - 16v² + 0v + 13

we see that 2v needs to be multiplied by 1v² to eliminate the first term

v²

2v - 2 | 2v³ - 16v² + 0v + 13

- (2v³ - 2v²)

0 - 14v²

multiply your estimate by your divisor and subtract from the dividend.

bring down the next term and repeat.

v² -7v

2v - 2 | 2v³ - 16v² + 0v + 13

- (2v³ - 2v²)

0 - 14v² + 0v

-(-14v² + 14v)

- 14v

repeat again

v² - 7v - 7

2v - 2 | 2v³ - 16v² + 0v + 13

- (2v³ - 2v²)

0 - 14v² + 0v

-(-14v² + 14v)

- 14v + 13

-(-14v + 14)

-1

and remainder gets put over the divisor and appended

v² - 7v - 7 - 1/(2v - 2)

13) Same process

5a + 1 | 40a³ - 12a² - 39a - 5

8a²

5a + 1 | 40a³ - 12a² - 39a - 5

-(40a³ + 8a²)

-20a² - 39a

8a² - 4a

5a + 1 | 40a³ - 12a² - 39a - 5

-(40a³ + 8a²)

-20a² - 39a

-(-20a² - 4a)

-35a - 5

8a² - 4a - 7

5a + 1 | 40a³ - 12a² - 39a - 5

-(40a³ + 8a²)

-20a² - 39a

-(20a² - 4a)

-35a - 5

-(-35a - 7)

2

8a² - 4a - 7 + 2/(5a + 1)

5 0

3 years ago