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Rufina [12.5K]
2 years ago
5

Can I see how long division works on these? pls no sketchy links

Mathematics
1 answer:
alexandr1967 [171]2 years ago
5 0

Answer:

Step-by-step explanation:

11) First write in decreasing exponential terms and fill in blanks with zeros.

Our goal is to eliminate all term in the dividend by subtraction

          ________________

2v - 2 |  2v³ - 16v² + 0v + 13

we see that 2v needs to be multiplied by 1v² to eliminate the first term

          <u>              v²                </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v²

multiply your estimate by your divisor and subtract from the dividend.

bring down the next term and repeat.

          <u>              v²    -7v       </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v² + 0v

                 <u>-(-14v² + 14v)</u>

                             - 14v

repeat again

<u />

          <u>              v²  -  7v  -  7 </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v² + 0v

                 <u>-(-14v² + 14v)</u>

                             - 14v + 13

                            <u>-(-14v + 14)</u>

                                          -1

and remainder gets put over the divisor and appended

v²  -  7v  -  7 - 1/(2v - 2)

13) Same process

          <u>                                      </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>              8a²                 </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

          <u>              8a² -    4a     </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

                   -(-<u>20a² -   4a)</u>

                                -35a - 5

          <u>              8a² -    4a  - 7  </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

                    -(<u>20a² -   4a)</u>

                                -35a - 5

                              -<u>(-35a - 7)</u>

                                           2

8a² - 4a - 7 + 2/(5a + 1)

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