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3 years ago

State the value of the discriminant for each equation. Then determine the number of real solutions of the equation.

Mathematics

1 answer:

matrenka [14]3 years ago

5 0

1) b^2 - 4ac = ( -2 )^2 - 4×( 0.5 ) × 2 = 4 - 4 = 0;
2) b^2 - 4ac =( -5)^2 - 4×2×20 = 25 - 160 = - 135 ;

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Find the slope of the line graphed below.

Lyrx [107]

Answer:

3over 2 because u go up by 3 and right by 2 u welcome

7 0

3 years ago

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Need help!! I have no clue

slega [8]

Answer:

41 over 24

Step-by-step explanation:

7 2/3 can be "translated" into 3 times 7 plus 2 which is 22, so now it's 22 over 3.

5 5/8 can be "translated" into 8 times 5 plus five is forty five, so now it's 45 over 8.

We now need a common denominator.

Multiples of 8: 8, 16, 24, 32

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24

24 are both multiples of 8 and 3.

Now you have to multiply 22 and 8 because 3 times 8 equals 24 and so you have to do it to the numerator.

22*8=176

Now you have to multiply 45 and 3 since 8 times 3 equals 24 and so you have to do it to the numerator, too.

45*3=135

All you have to do now is subtract 176 from 135 which is 41

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3 years ago

How do I do this I don't know how

murzikaleks [220]

Its easy all you do is add the time given or subtract it

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3 years ago

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3n + 8 = 53 I don’t understand how to find the n

olganol [36]

Answer:

n=15

Step-by-step explanation:

subtract 8 from both sides to get 3n=45

divide both sides by 3 to solve for n to get n=15

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Given that weekly demand curve of a local wine producer is p = 50 − 0.1q, and that

rusak2 [61]

Answer:

Z(p) = -10p² + 600p - 6500

Step-by-step explanation:

Demand curve p = 50 - 0.1 q

Total cost function C(q) = 1500 + 10q

where q is the number of bottles produced each day and p is the selling prices per bottle.

Now, p = 50 - 0.1 q

o.1 q = 50 - p

q = 500 - 10p

Revenue = price × quantity = p × q

= p ( 500 - 10p)

= 500 p - 10p²

Profit = total revenue - total cost

Let Profit be Z since profit is function of price, therefore

Z(p) = pq - C(q)

Z (p)= 500 p - 10p² - (1500 + 10q)

Substituting the value of q in above expression,

Z(p) = 500 p - 10p² - ( 1500 + 10 (500 - 10p))

Z(p) = 500p -10p² - 1500 -5000 + 100p

Z(p) = -10p² + 600p - 6500

So, the weekly profit as a function of price p is Z(p) = -10p² + 600p - 6500.

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3 years ago