Evaluate a/b + c2d for a= 6, b = 3., c = 4, and d = 5
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Answer:
Step-by-step explanation:
From this study:
The null hypothesis:
The altenative is:
This test is a two-tailed test.
However; we are told that the wives have 44 success out of 66, then the number of failures will be 22.
Then;
Similarly, the husbands have 18 success out of 46, then the number of failures will be 28
Then:
The pooled proportion
p = 0.55357
The estimated standard error S.E is:
=
= 0.0955
The Z test statitics can now be computed as:
Z = 2.88
Th p -value from the test statistics is:
p-value = 2P(Z > 2.88)
p- value = 2 P (1 - Z < 2.88)
p-value = 2 ( 1 - 0.998)
p-value = 2 ( 0.002)
p -alue = 0.004
Decision Rule:
Thus, at 0.01 significance level, we reject the null hypothesis because, p-value is less than that (i.e. significance level)
Conclusion:
We conclude that there is a significant difference between the proportions.