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Brrunno [24]
3 years ago
11

To change the size of a field or record by dragging its border a.resize b.magnify c.label d.enlarge

Computers and Technology
2 answers:
4vir4ik [10]3 years ago
6 0
A. Resize

By dragging the border of a field or record, you are either enlarging it or compressing it. Choices "b" and "d" are only half correct, as there is always the possibility of making it smaller. Hope this helps!
nasty-shy [4]3 years ago
5 0
Hi there!

The correct answer to this question is A. Resize.

Resizing makes things like text boxes, pictures, and other objects larger and more expanded or smaller and more contracted. Doing this can sometimes mess-up the aspect-ratio.

-<span>ASIAX </span><span>  </span><span>Frequent Answerer</span>


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A web page typically contains ________, which contains the formatting instructions for displaying the web page.
USPshnik [31]
HTML: Hypertext Markup Language. It's used in conjunction with CSS (Cascading Style Sheets), which implements presentation (adding color, positioning elements, etc.) and JavaScript (you'll often see this referred to as JS), which implements functionality (like clicking on buttons) for webpages.
3 0
3 years ago
Write a program that simulates flipping a coin repeatedly and continues until three consecutive heads. are tossed. At that point
quester [9]

Answer and Explanation:

#include <iostream>

#include <string>

#include <time.h>

#include <vector>

using namespace std;

//Takes user info

int user_info(string *name,char *gender){

   char G;

   cout<<"What is your name?: ";

   getline(cin, *name);

   cout<<"What is your gender(m/f):";

   cin>>G;

   cout<<endl;

   *gender = tolower(G);

   return 0;

}

//Toss coin(part 2)

bool coin_toss(double seed){

   double r;

   r = (double)seed/(double)RAND_MAX;

   //cout<<r;

   if (r<0.5) return true;

   return false;

}

//check results

float toss_result(vector<char> v,int *h){

   int num_heads=0;

   int num_toss = v.size();

   *h = 0;

   for(int i=0;i<num_toss;i++){

       if(v[i]=='h'){num_heads++;(*h)++;}

   }

   return (float)num_heads/(float)num_toss;

}

void show_result(int total_num,int head_num,float ratio){

   cout<<"it took you "<<total_num<<" tosses to get 3 heads in a row"<<endl;

   cout<<"on average you flipped heads "<<(ratio*100)<<"% of the time"<<endl;

}

int main()

{

   string name;

   char gender;

   string K; //Mr or Mrs

 

   cout<<"Welcome to coin toss! Get 3 heads in row to win!"<<endl;

 

   //part 1

   user_info(&name,&gender);

 

   if(gender == 'f') K = "Mrs.";

   else K = "Mr.";

 

   cout<<"Try to get 3 heads in a row. Good luck "<<K<<name<<"!"<<endl;

   char dummy = getchar();

 

   //part 2

   int num_toss;

   vector<char> toss_results;//store toss results

   bool result;//result of toss

   srand(time(0));

   while(true){

       //cout<<rand()<<endl;

       result = coin_toss(rand());

       cout<<"Press <enter> to flip"<<endl;

       while (1)

       {

           if ('\n' == getchar())

           break;

       }

     

 

     

       if(result) {toss_results.push_back('h');cout<<"HEAD"<<endl;}

       else {toss_results.push_back('t');cout<<"TAIL"<<endl;}

     

       num_toss = toss_results.size();

     

       if(num_toss>=3){

           if ((toss_results[num_toss-1] == 'h')&&(toss_results[num_toss-2] == 'h')&&(toss_results[num_toss-3] == 'h')){

               break;

           }

       }

   }

 

   //part 3

   float ratio_head;

   int num_of_heads;

   ratio_head = toss_result(toss_results,&num_of_heads);

 

   //part 4

 

   show_result(toss_results.size(),num_of_heads,ratio_head);

 

   return 0;

}

8 0
3 years ago
You have purchased a printer that has the capability to print in duplex mode so that users can print on both sides of a sheet of
fiasKO [112]

If you have purchased a printer that has the capability to print in duplex mode so that users can print on both sides of a sheet of paper. However, when users try to use this capability when they send a print job, documents are still printed on only one side. Then there might be a problem with (d) THE DUPLEX MODE NEEDS TO BE ENABLED ON THE DEVICE SETTINGS TAB IN THE PRINTER'S PROPERTIES.

Explanation:

  • If the duplex mode isn't enable on the printer setting, then the printer is still going to read that the output should come in a single page and not in the duplex mode.
  • When facing such a problem, the user should go to the "Device Settings" tab in the printer properties and change the required settings to print according to the users needs.

7 0
3 years ago
Which of the following questions will most likely be answered by displaying data on a line graph?
Artemon [7]
I'm pretty sure the answer is b
4 0
3 years ago
Write a java program called allDigitsOdd that returns whether every digit of a positive integer is odd. Return true if the numbe
Vlada [557]

Answer:

public class Digits

{

   public static boolean allDigitsOdd(int num)

   {

       boolean flag=true;

       int rem;

       while(num>0)

       {

           rem=num%10;

           num=num/10;

           if(rem%2==0)    // if a even digit found immediately breaks out of loop

           {

               flag=false;

               break;

           }

       }

       return flag;     //returns result

   }

   public static void main(String args[])

   {

       System.out.println(allDigitsOdd(1375));    //returns true as all are odd digits

   }

}

OUTPUT :

true

Explanation:

Above program has 2 static methods inside a class Digits. Logic behind above function is that a number is divided by 10 until it is less than 0. Each time its remainder by 0 is checked if even immediately breaks out of the loop.

4 0
3 years ago
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