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2 years ago

Class Main {

Computers and Technology

1 answer:

Ganezh [65]2 years ago

4 0

Answer:

class Main {

static void printPowers(int howMany, int nrRows) {

for(int n=1; n<=nrRows; n++) {

for(int power = 1; power<=howMany; power++) {

System.out.printf("%d ", (int) Math.pow(n, power));

}

System.out.println();

}

public static void main(String[] args) {

printPowers(3, 5);

}

class Main {

static void printPowers(int howMany, int nrRows) {

int n = 1;

do {

int power = 1;

do {

System.out.printf("%d ", (int) Math.pow(n, power));

power++;

} while (power <= howMany);

System.out.println();

n++;

} while (n <= nrRows);

}

public static void main(String[] args) {

printPowers(3, 5);

}

Explanation:

The for loop gives the cleanest, shortest code.

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3 years ago

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3 years ago

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Write a program that asks the user to input a set of floating-point values. When the user enters a value that is not a number, g

Lady_Fox [76]

Answer:

Check the explanation

Explanation:

// include the necessary packages

import java.io.*;

import java.util.*;

// Declare a class

public class DataReader

{

// Start the main method.

public static void main(String[] args)

{

// create the object of scanner class.

Scanner scan = new Scanner(System.in);

// Declare variables.

boolean done = false;

boolean done1 = false;

float sum = 0;

double v;

int count = 0;

// start the while loop

while (!done1)

{

// start the do while loop

{

// prompt the user to enter the value.

System.out.println("Value:");

// start the try block

try

{

// input number

v = scan.nextDouble();

// calculate the sum

sum = (float) (sum + v);

}

// start the catch block

catch (Exception nfe)

{

// input a character variable(\n)

String ch = scan.nextLine();

// display the statement.

System.out.println(

"Input Error. Try again.");

// count the value.

count++;

break;

}

// end do while loop

while (!done);

// Check whether the value of count

// greater than 2 or not.

if (count >= 2)

{

// display the statement on console.

System.out.println("Sum: " + sum);

done1 = true;

}

Sample Output:

Value:

ten

Input Error. Try again.

Value:

nine

Input Error. Try again.

Sum: 29.0

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3 years ago

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Find the equation of a line which has 10 points the following two coordinates: (4, 0) and (3, 4)

alex41 [277]

Answer:

The equation of the line is y = -4·x + 16

10 points on the line include;

(0, 16), (1, 12), (2, 8), (3, 4), (4, 0), (5, -4), (6, -8), (7, 12), (8, -16), (9, -20), and (10, -24)

Explanation:

The given points through which the line passes are;

(4, 0) and (3, 4)

The slope, 'm', of the line is given as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Therefore, the slope of the line is (4 - 0)/(3 - 4) = -4

In point and slope form we can get;

$\dfrac{y-0}{x-4} = -4$

The equation of the line in point and slope form is therefore;

y = -4·(x - 4) = -4·x + 16

The equation of the line in slope and intercept form is

y = -4·x + 16

10 points on the line are obtained using the equation of the line and the desired x-values input into cells on MS Excel and presented here as follows;

(0, 16), (1, 12), (2, 8), (3, 4), (4, 0), (5, -4), (6, -8), (7, 12), (8, -16), (9, -20), and (10, -24)

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