<em>=</em><em> </em><em>Option</em><em> </em><em>b</em><em> </em><em>Minicomputer ..........</em>
Answer:
import datetime
user = input("Enter date in yyyy,m,d: ").split(",")
int_date = tuple([int(x) for x in user])
year, month, day =int_date
mydate = datetime.datetime(year, month, day)
print(mydate)
x = mydate.strftime("%B %d, %Y was a %A")
print(x)
Explanation:
The datetime python module is used to create date and time objects which makes it easy working with date-time values. The user input is converted to a tuple of integer items, then they are converted to date time objects and parsed to string with the strftime method.
Answer:
open-source
Explanation:
open-souce software allows any user to submit modifications of the source code
Answer:
B
Explanation:
When you initialize an instance of FunEvent(tags, year) and assign it to bc. The instance variables in this case are: self.tags = ["g", "ml"] and self.year = 2022. But then you alter tags, which will also change self.tags, since self.tags is a reference to the list you passed in as an argument. This is not the case when you do year=2023 because, first of all, integers are not mutable, and also because even if somehow integers were mutable, you're not changing the object in-place, you're simply changing the where the "variable" is pointing to. So for example if you did tags = ["g", "ml", "bc"] instead of tags.append("bc"), it would also not change the value of the instance variable "tags", because you wouldn't be changing the object in-place. So when you print(bc), the instance variables will be ["g", "ml", "bc"] and 2022. When you try to print an object, it call try to convert it into a string using the __str__ magic method. In this case it will return a string formatted as "Event(tags={self.tags}, year={self.year}) which will output "Event(tags=['g', 'ml', 'bc'], year=2022)" So the correct answer is B
